Question

我在PHP中创建了一个数据库类，我只想要OOP样式而不是程序样式。这是我试图关闭这个错误的代码。此功能导致问题。

class MySQLDatabase
{
    private $connection;
    public $message;

    /**
     * MySQLDatabase constructor.
     */
    public function __construct()
    {
        $this->open_connection();
    }

    //Object oriented style
    public function open_connection()
    {
        // the constant comes form config
        $this->connection = new mysqli(DB_SERVER, DB_USER, DB_PASS, DB_NAME);
        /*
         * This is the "official" OO way to do it,
         */

        if ($this->connection->connect_error) {
            die('Connect Error (' . mysqli_connect_errno() . ') ' . mysqli_connect_error());
        } else {
            $this->message = "Success... " . $this->connection->host_info;
        }
    }

    public function close_connection(){
        if (isset($this->connection)) {
            mysqli_close($this->connection);
            unset($this->connection);
        }
    }
}

Answer 1

public function close_connection()
    {
        if(isset($this->connection))
        {
            $this->connection->close();
            unset($this->connection);
        }
    }

Answer 2

您正在以面向对象的方式创建新连接，因此您需要在连接对象上调用它的close方法。

所以你的代码看起来像这样，

public function close_connection()
{
    if(isset($this->connection))
    {
        $this->connection->close();
        unset($this->connection);
    }
}

使用数据库类在php中关闭连接

2 个答案: