Question

我将输出作为字符串。但价值在关键＆amp;值

            var buffer = Array<UInt8>(repeating: 0, count: 4096)
        if ( aStream == inputStream){

            while (inputStream.hasBytesAvailable){
                let len = inputStream.read(&buffer, maxLength: buffer.count)
                if(len > 0){
                    let output  = NSString(bytes: &buffer, length: buffer.count, encoding: String.Encoding.utf8.rawValue)

                    if (output != ""){
                        NSLog("server said: %@", output!)
                        receivingData = output as! String
                        delegate.socketReceiveData(responce: receivingData)
                    }

                }

            }
        }

数据正在字典中，但对象在字符串中无法隐藏。来自服务器的output = {“password": "12345", "method": "login", "mail_id": "abc@gmail.com"} 但输出是字符串如何读取方法，密码等的值...

Answer 1

这是一个JSON字符串"{"password": "12345", "method": "login", "mail_id": "abc@gmail.com"}"

您可以将其转换为字典，如下所示

let data = output!.data(using: String.Encoding.utf8, allowLossyConversion: false)

do {
  let json = try JSONSerialization.jsonObject(with: data!, options: [])
  let dict = json as? [String: Any]
  let method = dict?["method"]
  print(method)
}
catch {
  print(error)
}

你也可以试试 jsonObject(with stream: InputStream, options opt: JSONSerialization.ReadingOptions = []) throws -> Any方法并将输入流提供给它

修改

尝试此代码

var buffer = Array<UInt8>(repeating: 0, count: 4096)
if ( aStream == inputStream){

  while (inputStream.hasBytesAvailable){
    let len = inputStream.read(&buffer, maxLength: buffer.count)
    if(len > 0){

      let data = Data(bytes: &buffer, count: buffer.count)

      do {
        let json = try JSONSerialization.jsonObject(with: data!, options: [])
        let dict = json as? [String: Any]
        let method = dict?["method"]
        print(method)
      }
      catch {
        print(error)
      }

//          if (output != ""){
//            NSLog("server said: %@", output!)
//            receivingData = output as! String
//            delegate.socketReceiveData(responce: receivingData)
//          }

    }

  }
}

Answer 2

使用此

let strf = "{\"name\":\"maan\"}"


        let data = strf.data(using: String.Encoding.utf8)

         do {
            guard let toddo = try JSONSerialization.jsonObject(with: data!, options: []) as? [String: AnyObject] else
            {

                print("error trying to convert data to JSON")
                return
            }

            print(toddo);
        }
        catch {
            print(error)
        }

如何将输出作为字典流 - 套接字

2 个答案:

修改