我正在尝试从Nokogiri节点元素中删除属性。
这是第一个节点元素:
=> #(Element:0x3fed0eaf2ef0 {
name = "ins",
namespace = #(Namespace:0x3fed0ed24408 { prefix = "w", href = "http://schemas.openxmlformats.org/wordprocessingml/2006/main" }),
attributes = [
#(Attr:0x3fed0eb1e528 { name = "id", namespace = #(Namespace:0x3fed0ed24408 { prefix = "w", href = "http://schemas.openxmlformats.org/wordprocessingml/2006/main" }), value = "0" }),
#(Attr:0x3fed0eb1e514 { name = "author", namespace = #(Namespace:0x3fed0ed24408 { prefix = "w", href = "http://schemas.openxmlformats.org/wordprocessingml/2006/main" }), value = "Mitchell Gould" })
#(Attr:0x3fed0eb1e500 { name = "date", namespace = #(Namespace:0x3fed0ed24408 { prefix = "w", href = "http://schemas.openxmlformats.org/wordprocessingml/2006/main" }), value = "2016-10-15T14:43:00Z" })]
})
当我这样做时:
first = all_ins_nodes.first.remove_attribute("name")
first => nil
我只想删除属性而不删除整个节点元素。我怎么能这样做?
答案 0 :(得分:1)
就在这里
first = all_ins_nodes.first.remove_attribute("name")
应该分成多行
first = all_ins_node.first
first.remove_attribute("name")
原因是.remove_attribute
显然会返回nil。您希望指针指向.first
调用的结果。