在两个字符串之间搜索并保存字符串

Question

我想从日志文件中获取以下字符串，

Name: OnError
Computer: 
Operator: 
Source Name: 
Source GUID: 
Execution GUID: 
Message: A connection could not be made to the data source with the DataSourceID of 'xyz', Name of 'abc'.
Start Time: 2016-09-29 05:40:08
End Time: 2016-09-29 05:40:08
End Log

我搜索字符串的关键字是OnError。从字符串OnError到End Log，我需要采取并且必须存储在数组中。

请提出您的建议，以便编写上述代码

Answer 1

您可以使用正则表达式轻松完成

mapper(Apple, appleTable, properties={
    "appleBloggers": relationship(Blogger,
                                  secondary=recipeTable.join(blogTable, recipeTable.c.id == blogTable.c.recipeId),
                                  primaryjoin=appleTable.c.id == recipeTable.c.appleId,
                                  secondaryjoin=blogTable.c.bloggerId == bloggerTable.c.id)
})

Answer 2

JsonWriter writer = new JsonWriter(out, true);

我假设您在此示例中只有一次出现（OnError和End Log）给定模式。如果此模式出现多次，您可以展开它。首先找到包含OnError的行，然后读取直到包含End Log的行。