我的查询目的是输出角色为"PPC"
的所有电子邮件以及这些PPC所属的"paygroups"
。
paygroup
可以有多个PPCs
。 PPC
可能包含email address 1
和/或email address 2
。 当我使用测试paygroup(BOX)
时,查询工作正常,但当我对该行进行评论以查询所有paygroups
以返回所有PPCs
paygroups
时我收到错误"single-row subquery returns more than one row"
。
SELECT
auth.paygroup,
per.NAME,
per.email_address AS "Personal email",
per.email_address2 AS "Business email"
FROM ps_personal_data per
INNER JOIN ps_ts_ee_auth auth
ON auth.emplid=per.emplid
INNER JOIN PS_SMS_SUBSCRB_TBL SUB
ON SUB.SUBSCRIBER_ID = AUTH.PAYGROUP
WHERE 1=1
AND SUB.EFFDT = (SELECT max (SUB2.effdt) FROM PS_SMS_SUBSCRB_TBL SUB2
WHERE SUB.SUBSCRIBER_ID = SUB2.SUBSCRIBER_ID AND SUB.EFF_STATUS = 'A')
AND auth.user_name = (SELECT R1.USER_NAME FROM PS_TS_CONTACT_ROLE R1
WHERE 1=1
AND R1.contact_role = 'PPC'
--AND R1.paygroup = 'BOX' --commenting this line out causes the error. It works fine when line is active
AND R1.action_dt = (SELECT MAX (R2.action_dt)
FROM PS_TS_CONTACT_ROLE R2
WHERE 1=1
AND R1.paygroup = R2.paygroup
AND R1.contact_role =
R2.contact_role))
答案 0 :(得分:1)
SELECT
auth.paygroup,
per.NAME,
per.email_address AS "Personal email",
per.email_address2 AS "Business email"
FROM ps_personal_data per
INNER JOIN ps_ts_ee_auth auth
ON auth.emplid=per.emplid
INNER JOIN PS_SMS_SUBSCRB_TBL SUB
ON SUB.SUBSCRIBER_ID = AUTH.PAYGROUP
WHERE 1=1
AND SUB.EFFDT = (SELECT max (SUB2.effdt) FROM PS_SMS_SUBSCRB_TBL SUB2
WHERE SUB.SUBSCRIBER_ID = SUB2.SUBSCRIBER_ID AND SUB.EFF_STATUS = 'A')
AND auth.user_name in (SELECT R1.USER_NAME FROM PS_TS_CONTACT_ROLE R1 -- Change = to in
WHERE 1=1
AND R1.contact_role = 'PPC'
AND R1.paygroup = 'BOX' --commenting this line out causes the error. It works fine when line is active
AND R1.action_dt = (SELECT MAX (R2.action_dt)
FROM PS_TS_CONTACT_ROLE R2
WHERE 1=1
AND R1.paygroup = R2.paygroup
AND R1.contact_role =
R2.contact_role))