Question

如何将表序列化为json数组，以便每个数组元素都包含代表一个表行的json对象：

[
{ name: "variable1", valuetostore: "a-b", totaltype: "Lowest" },
{ name: "variable2", valuetostore: "c-d", totaltype: "Highest" }
]

我尝试了下面的代码，但这会生成具有名称和值属性的对象，并且数组中的成员数多于表行中的成员数。

它也序列化了隐藏的第一行。它是行添加的模板行，不应该在结果中使用。

$(function() {
  $("#btnShow").on("click", function() {
    console.log($("#myForm").serializeArray());
  });
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<div class="modal" id="reportVariables" tabindex="-1" role="dialog" aria-labelledby="reportVariablesLabel">
  <div class="modal-dialog modal-lg" role="document">
    <div class="modal-content">
      <div class="modal-body">
        <form id="myForm">
          <table class="table table-condensed table-striped" id="reportVariablesTable">
            <thead>
              <tr>
                <th>Name</th>
                <th>Value</th>
                <th>Calculate</th>
              </tr>
            </thead>
            <tbody>
              <!-- table contains one hidden rows which should not -->
              <tr style='display:none'>
                <td>
                  <input type="text" name="name">
                </td>

                <td>
                  <textarea name="valuetostore"></textarea>
                </td>

                <td>
                  <select class="totaltype-select" id="totaltype" name="totaltype">
                    <option value=""></option>
                    <option value="Sum">Summary</option>
                    <option value="Lowest">Smallest</option>
                    <option value="Highest">Biggers</option>
                  </select>
                </td>
              </tr>

              <!-- other are data rows which should sent -->
              <tr>
                <td>
                  <input type="text" name="name" value="variable1">
                </td>

                <td>
                  <textarea name="valuetostore">a-b</textarea>
                </td>

                <td>
                  <select class="totaltype-select" id="totaltype" name="totaltype">
                    <option value=""></option>
                    <option value="Sum">Summary</option>
                    <option value="Lowest" selected>Smallest</option>
                    <option value="Highest">Biggers</option>
                  </select>
                </td>
              </tr>
              <tr>
                <td>
                  <input type="text" name="name" value="variable2">
                </td>

                <td>
                  <textarea name="valuetostore">c-d</textarea>
                </td>

                <td>
                  <select class="totaltype-select" id="totaltype" name="totaltype">
                    <option value=""></option>
                    <option value="Sum">Summary</option>
                    <option value="Lowest" >Smallest</option>
                    <option value="Highest" selected>Biggers</option>
                  </select>
                </td>
              </tr>

            </tbody>
          </table>
          <button id="btnShow" type="button">
            Show
          </button>
        </form>

      </div>
    </div>
  </div>
</div>

Answer 1

您可以将nth-child选择器与n+2一起使用，仅选择tr＆gt; = 2：

#myForm tbody tr:nth-child(n+2)

但是，结果将不是一个对象数组，其中每个对象都是一个行的对象。结果将是一个对象数组，其中每个select / input / textarea本身就是一个对象。

您可以使用each()上的trs功能覆盖所有这些功能，以获得预期效果。

以下是两个选项的示例：

＆＃13;

$(function() {
  $("#btnShow1").on("click", function() {
    console.log($("#myForm tbody tr:nth-child(n+2) textarea,#myForm tbody tr:nth-child(n+2) input,#myForm tbody tr:nth-child(n+2) select").serializeArray());
  });

  $("#btnShow2").on("click", function() {
    var ar = [];
    $("#myForm tbody tr:nth-child(n+2)").each(function() {
      rowData = $(this).find('input, select, textarea').serializeArray();
      var rowAr = {};
      $.each(rowData, function(e, v) {
        rowAr[v['name']] = v['value'];
      });
      ar.push(rowAr);
    });
    console.log(ar)
  });
});

＆＃13;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<div class="modal" id="reportVariables" tabindex="-1" role="dialog" aria-labelledby="reportVariablesLabel">
  <div class="modal-dialog modal-lg" role="document">
    <div class="modal-content">
      <div class="modal-body">
        <form id="myForm">
          <table class="table table-condensed table-striped" id="reportVariablesTable">
            <thead>
              <tr>
                <th>Name</th>
                <th>Value</th>
                <th>Calculate</th>
              </tr>
            </thead>
            <tbody>
              <!-- table contains one hidden rows which should not -->
              <tr style='display:none'>
                <td>
                  <input type="text" name="name">
                </td>

                <td>
                  <textarea name="valuetostore"></textarea>
                </td>

                <td>
                  <select class="totaltype-select" id="totaltype" name="totaltype">
                    <option value=""></option>
                    <option value="Sum">Summary</option>
                    <option value="Lowest">Smallest</option>
                    <option value="Highest">Biggers</option>
                  </select>
                </td>
              </tr>

              <!-- other are data rows which should sent -->
              <tr>
                <td>
                  <input type="text" name="name" value="variable1">
                </td>

                <td>
                  <textarea name="valuetostore">a-b</textarea>
                </td>

                <td>
                  <select class="totaltype-select" id="totaltype" name="totaltype">
                    <option value=""></option>
                    <option value="Sum">Summary</option>
                    <option value="Lowest" selected>Smallest</option>
                    <option value="Highest">Biggers</option>
                  </select>
                </td>
              </tr>
              <tr>
                <td>
                  <input type="text" name="name" value="variable2">
                </td>

                <td>
                  <textarea name="valuetostore">c-d</textarea>
                </td>

                <td>
                  <select class="totaltype-select" id="totaltype" name="totaltype">
                    <option value=""></option>
                    <option value="Sum">Summary</option>
                    <option value="Lowest" >Smallest</option>
                    <option value="Highest" selected>Biggers</option>
                  </select>
                </td>
              </tr>

            </tbody>
          </table>
          <button id="btnShow1" type="button">
            Options #1
          </button><br />
          <button id="btnShow2" type="button">
            Options #2
          </button>
        </form>

      </div>
    </div>
  </div>
</div>

＆＃13;

Answer 2

您可以使用SerializeFromTable JQuery插件序列化任何具有或不具有表单元素的表。
无需用

标签包装表格。
它很简单（其中data-columnTitle是您想要的ur / json / json数组对象中的关键字段）：

let tabledata = $("#example1").serializeFromTable({
                  columnNameBy:"data-columnTitle"
                });

有关更多选项，请查看以下链接：serializeFromTable Plugin

如何将表行序列化为json对象

2 个答案: