我希望能够为用户分配车辆注册,当用户登录网站时,他们的主页应该有他们拥有的车辆注册列表。
但是我无法让模型类过滤外键。
views.py
@login_required
def home(request):
# This is the basic user landing Page
veh_list = Vehicle.objects.filter(UserProfile.user)
return render(request, 'portal/home.html', {"veh_list": veh_list})
model.py
from django.db import models
from django.contrib.auth.models import User
# Create your models here.
class UserProfile(models.Model):
# This line is required. Links UserProfile to a User model instance.
user = models.OneToOneField(User)
# The additional attributes we wish to include.
compName = models.CharField(max_length = 20)
milkco = models.IntegerField()
# Override the __unicode__() method to return out something meaningful!
def __unicode__(self):
return self.user.username
class Vehicle(models.Model):
vehid = models.CharField(max_length = 10)
company = models.ForeignKey(UserProfile, default = 1)
class Meta:
db_table = "vehicle"
def __unicode__(self):
return self.vehid
home.html的
<!DOCTYPE html>
{% extends 'portal/base.html' %}
{% block title %}{{user.first_name }} {{ user.last_name }} Portal{% endblock %}
{% block content %}
<p>This is the home Page</p>
{% if user.is_authenticated %}
<h4>Optiload says... hello {{ user.first_name }} {{ user.last_name }}!</h4>
{% endif %}
{% for veh in veh_list %}
{{ veh}}
{% endfor %}
{% if user.is_authenticated %}
<a href="/logout/">Logout</a><br/>
{% endif %}
{% endblock %}
有人可以帮我解决我出错的地方吗?
由于
答案 0 :(得分:1)
Django提供了一种强大而直观的方式来“跟踪”查找中的关系,在后台自动处理SQL JOIN。要跨越关系,只需使用跨模型的相关字段的字段名称,用双下划线分隔,直到到达所需的字段。
所以你的查询应该是
veh_list = Vehicle.objects.filter(company__user=request.user)
答案 1 :(得分:0)
您无法使用未命名的参数进行查询:
Vehicle.objects.filter(UserProfile.user)
在这种情况下,您需要:
Vehicle.objects.filter(company=[your user])