Question

为什么我不能告诉模拟它应该期望一个类的实例而不显式给出类型？这就是我的意思：

val myClass = new MyClass(...)
val traitMock = mock[MyTrait]
(traitMock.mymethod _).expects(myClass).returning(12.3)

不起作用，而

val myClass: MyClass = new MyClass(...)
val traitMock = mock[MyTrait]
(traitMock.mymethod _).expects(myClass).returning(12.3)

确实有效。为什么这种类型无法推断？

我在build.sbt的测试部分是

libraryDependencies ++= Seq(
  "org.scalatest" %% "scalatest" % "3.0.0" % "test"
    exclude("org.scala-lang", "scala-reflect")
    exclude("org.scala-lang.modules", "scala-xml")
)

libraryDependencies += "org.scalamock" %% "scalamock-scalatest-support" % "3.3.0" % "test"

因为我被问到MyClass（这里是SpacePoint）：

trait SpacePoint {
  val location: SpaceLocation
}
val sp = new SpacePoint {
  override val location: SpaceLocation = new SpaceLocation(DenseVector(1.0, 1.0))
}

Answer 1

实际上对我有用。让我在代码中提到类型推断：

val myClass = new MyClass(...)

与ScalaMock无关，但由scala本身保证。下面我将使用库版本和类的来源指定工作示例。

测试库：

"org.scalatest" %% "scalatest" % "2.2.4" % "test",
"org.scalamock" %% "scalamock-scalatest-support" % "3.2.2" % "test"

课程的源代码：

class MyClass(val something: String)

trait MyTrait {

  def mymethod(smth: MyClass): Double
}

测试源代码：

import org.scalamock.scalatest.MockFactory
import org.scalatest.{Matchers, WordSpec}

class ScalamockTest extends WordSpec with MockFactory with Matchers {

  "ScalaMock" should {

    "infers type" in {
      val myClass = new MyClass("Hello")
      val traitMock = mock[MyTrait]
      (traitMock.mymethod _).expects(myClass).returning(12.3)

      traitMock.mymethod(myClass) shouldBe 12.3
    }
  }
}

希望它有所帮助。一旦您提供更多详细信息，将准备好更新答案。

在Scalamock中期望模拟的特定实例

1 个答案: