使用maven程序集在文件夹中构建zip

时间:2016-10-25 09:54:50

标签: pom.xml

我能够构建一个拉链,很高兴。但是当我解压缩时,内容不会打包在一个文件夹(我的文件名)中。我看到了许多问题并且紧随其后,所有问题都很相似任何人都可以帮我制作拉链。 在此先感谢.......

v = VideoReader('sample.avi','CurrentTime',1);
figure1=figure('unit','normalized','Position',[0.2 0.2 0.4 0.6]);
axes1=subplot(3,1,1);
axes2=subplot(3,1,2);
axes3 = subplot(3,1,3);

counter=0;
difference=[];
video_frame=readFrame(v);
while hasFrame(v)
    lastframe=video_frame;
    video_frame = readFrame(v);
    counter=counter+1;

    imshow(video_frame,'Parent',axes1);
    [a,b]=histcounts(video_frame(:,:,1));
    plot(b(1:end-1),a,'Parent',axes2);

    difference=[difference sum(abs(histcounts(video_frame,0:255)-histcounts(lastframe,0:255)))];
    bar(1:counter,difference,'Parent',axes3);
    waitforbuttonpress
end
  [~,onedistinguished]=max(difference);
  %defining a threshold like every value that is bigger 4000
   multidistinguished=find(difference>4000);

  disp(['majorly changed at: ' num2str(distinguished)]);

1 个答案:

答案 0 :(得分:-1)

在程序集目录下的xml文件中有点错误。我们需要为baseIncludeDirectory标记设置“true”....