Question

我正在查询API，但有时候API会在随机执行脚本后发送503,400等错误。

我试图抓住它，但无论我如何尝试，我的脚本都停止了，如果脚本停止，我需要继续手动检查。

有没有办法捕获Try块中发生的每个错误？

PHP致命错误：未捕获异常：客户端错误：GET http://xxxxxxxxxx导致400 Bad Request响应：

    while ($x <= 5000) {
    try {
        sleep(2);
        $formattedResponse = $apaiIO - > runOperation($lookup);
        $xml = simplexml_load_string($formattedResponse);
    } catch (\GuzzleHttp\ Exception\ ServerException $e) {
        $code = $e - > getResponse() - > getStatusCode();
        echo "<strong>Error:</strong> ".$e - > getResponse() - > getReasonPhrase().
        " <strong>Code:</strong> ".$code.
        "<br>";
        switch ($code) {
            // throttle request/service unavailable;
            case 503:
                sleep(2);
            default:
                sleep(2);
                throw new Exception($e - > getResponse() - > getReasonPhrase(), $code);
        }
    } catch (\Exception $e) {
        sleep(2);
        //Last error was thrown by this line.

        throw new Exception($e - > getMessage(), $e - > getCode());
    }

    //do script stuff here.
}

Answer 1

使用continue并将整个try-catch保留在另一个循环中不应该再破坏脚本。

$success=false;
    $cattempt=0;// current attempt;
    while($cattempt<=2){
        try{
            sleep(2);
            $xml = simplexml_load_string($formattedResponse);
            $success=true;
        }catch (\GuzzleHttp\Exception\ServerException $e) {
            $code=$e->getResponse()->getStatusCode();
            echo "<strong>Error:</strong> ".$e->getResponse()->getReasonPhrase()." <strong>Code:</strong> ".$code."<br>";
            switch($code){
                // throttle request/service unavailable;
                case 503:
                    sleep(2);
                    $cattempt++; // will try again.
                    break; // break from switch
                default: 
//                  sleep(2);
//                  $cattempt++;
                    break 2; // break from swtich and while loop
//                  throw new Exception($e->getResponse()->getReasonPhrase(),$code);
            }
        }
        catch (\Exception $e) {
            echo "<strong>Error:</strong> ".$e->getMessage()." <strong>Code:</strong> ".$e->getCode()."<br>";
            sleep(2);
            break; // break from while;
//          throw new Exception($e->getMessage(),$e->getCode());
        }
        if($success) break;
    }
    if(!$success){
        continue; // go to next ASIN.
    }

如何尝试捕获并继续PHP中的脚本

1 个答案: