Question

正如标题所说......当用户点击Java Swing应用程序中的按钮时，我尝试使用以下代码执行PHP脚本：

URL url = new URL( "http://www.mywebsite.com/my_script.php" );
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.connect();

但没有任何反应...... 有什么问题吗？

Answer 1

我认为你错过了下一步，例如：

InputStream is = conn.getInputStream();

HttpURLConnection基本上只打开connect上的套接字，以便执行您需要执行的操作，例如调用getInputStream()或更好地getResponseCode()

URL url = new URL( "http://google.com/" );
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
if( conn.getResponseCode() == HttpURLConnection.HTTP_OK ){
    InputStream is = conn.getInputStream();
    // do something with the data here
}else{
    InputStream err = conn.getErrorStream();
    // err may have useful information.. but could be null see javadocs for more information
}

Answer 2

final URL url = new URL("http://domain.com/script.php");
final InputStream inputStream = new InputStreamReader(url);
final BufferedReader reader = new BufferedReader(inputStream).openStream();

String line, response = "";

while ((line = reader.readLine()) != null)
{
    response = response + "\r" + line;
}

reader.close();

“回复”将保留页面文本。您可能想要回车（取决于操作系统，尝试\ n，\ r或两者的组合）。

希望这有帮助。

如何从Java代码调用PHP脚本？

2 个答案: