我是多线程的新手,如果这个方法是线程安全的,我很困惑,因为我没有在HttpURLConnection conn上做新的................. .....................
protected byte[] someMethod(Authenticator authenticator, String url, boolean doPost) throws Exception {
try {
URL aUrl = new URL(url);
strBldr = new StringBuilder();
AuthenticatedURL.Token token = new AuthenticatedURL.Token();
TestConnectionConfigurator connConf = new TestConnectionConfigurator();
AuthenticatedURL authUrl = new AuthenticatedURL(authenticator, connConf);
HttpURLConnection conn = authUrl.openConnection(aUrl, token);
if (!connConf.invoked)
throw new IOException("failed to invoked");
String tokenStr = token.toString();
if (doPost) {
conn.setRequestMethod("POST");
conn.setDoOutput(true);
}
conn.setRequestProperty("Accept", "application/octet-stream");
conn.setDoOutput(true);
conn.connect();
if (conn.getResponseCode() == HttpURLConnection.HTTP_OK) {
BufferedInputStream in = new BufferedInputStream(
conn.getInputStream());
ByteArrayOutputStream byteArraySt = new ByteArrayOutputStream();
int counter;
while ((counter = in.read()) != -1) {
byteArraySt.write(counter);
}
byte [] bArray = new byte[byteArraySt.toByteArray().length];
bArray = byteArraySt.toByteArray();
in.close();
return bArray;
}
答案 0 :(得分:0)
作为编写线程安全代码的一般规则,您必须关注可变共享状态。本地变量不会被共享,因此它们不是一个问题。
您的代码应该是线程安全的,但是您应该检查传递给该方法的authenticator
对象(因此可以由不同的线程共享)是否实际上是线程安全的。