Question

我试图弄清楚我的Cassandra集群的吞吐量，并且无法弄清楚如何使用nodetool来实现这一目标。以下是示例输出：

Starting NodeTool
Keyspace: realtimetrader
Read Count: 0
Read Latency: NaN ms.
Write Count: 402
Write Latency: 0.09648756218905473 ms.
Pending Flushes: 0
        Table: currencies
        SSTable count: 1
        Space used (live): 5254
        Space used (total): 5254
        Space used by snapshots (total): 0
        Off heap memory used (total): 40
        SSTable Compression Ratio: 0.0
        Number of keys (estimate): 14
        Memtable cell count: 1608
        Memtable data size: 567
        Memtable off heap memory used: 0
        Memtable switch count: 0
        Local read count: 0
        Local read latency: NaN ms
        Local write count: 402
        Local write latency: 0.106 ms
        Pending flushes: 0
        Bloom filter false positives: 0
        Bloom filter false ratio: 0,00000
        Bloom filter space used: 24
        Bloom filter off heap memory used: 16
        Index summary off heap memory used: 16
        Compression metadata off heap memory used: 8
        Compacted partition minimum bytes: 125
        Compacted partition maximum bytes: 149
        Compacted partition mean bytes: 149
        Average live cells per slice (last five minutes): 0.0
        Maximum live cells per slice (last five minutes): 0
        Average tombstones per slice (last five minutes): 0.0
        Maximum tombstones per slice (last five minutes): 0

我运行命令：

nodetool cfstats

得到这个，然后减去后者，＆＃34;本地读数：＆＃34;从较早的一个。但我不确定＆＃34; Local＆＃34;这意味着什么它是否意味着它在该节点的本地和5个节点的环中，我应该将该值乘以5？或者简单的减法会给我正确的结果吗？

另外，我应该考虑使用哪种JMX bean来获取这些＃？p？

Answer 1

看看这个nodetool cfstats。

我认为你要找的是'读延迟'和'写延迟'。这些字段表示您的群集中的读/写速度有多快。

Cassandra：read / s write / s

1 个答案: