Question

我有这个数据

ID DATEREG     REQUEST
1  2016-10-24  PAPER
2  2016-10-24  PENCIL
3  2016-10-24  BALLPEN
4  2016-10-25  PAPER
5  2016-10-26  PENCIL

这是我用来计算总请求的查询。

    $rows = '';
    $query = "SELECT id,count(*) as total,date,request FROM list GROUP BY date,request ORDER BY id DESC LIMIT 10";
    $result = mysqli_query($con,$query);
    $total_rows =  $result->num_rows;
    if($result) 
    {
    $rowsv1 = mysqli_fetch_all($result, MYSQLI_ASSOC);
    print "<pre>";
    echo print_r($rowsv1);
    print "</pre>";
    }

请求仅显示1（DESC顺序）的示例结果：

[0] => Array
    (
        [id] => 5
        [total] => 3
        [datereg] => 2016-10-24
        [request] => PAPER
    )

我想看起来像这样：

[0] => Array
    (
        [id] => 5
        [total] => 3
        [datereg] => 2016-10-24
        [request1] => 1(total of PAPER)
        [request2] => 2(total of PENCIL)
        [request3] => 3(total of BALLPEN)
    )

由于

Answer 1

我稍微更改了您的查询，现在首先按请求按日期分组。但是你必须在php中聚合结果才能将所有3个请求放在一个数组项中

   $query = "SELECT id,count(*) as total,date,request FROM list GROUP BY request, date ORDER BY id DESC LIMIT 10";

否则，它将按日期分组，这将导致将给定日期的结果聚合为仅一个请求。

如何在数组中回显GROUP BY mysql？

1 个答案: