Question

我有以下数据的Cassandra表：

cqlsh:test> SELECT * FROM test1 WHERE solr_query='{"q":"address:*"}';

name  | address                      | age | solr_query
-------+------------------------------+-----+------------
 test3 |          road3 united states |  23 |       null
 test4 |              road 123 canada |  23 |       null
 test2 |        street2 united states |  22 |       null
 test1 | 123 california united states |  21 |       null
 test5 |      123 Texas united states |  23 |       null

with schema：

<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<schema name="TestSolrSchema" version="1.5">
<types>
<fieldType class="org.apache.solr.schema.StrField" name="StrField"/>
<fieldType class="org.apache.solr.schema.TrieIntField" name="TrieIntField"/>
</types>
<fields>
<field docValues="true" indexed="true" multiValued="false" name="name" stored="true" type="StrField"/>
<field docValues="true" indexed="true" multiValued="false" name="address" stored="true" type="StrField"/>
<field docValues="true" indexed="true" multiValued="false" name="age" stored="true" type="TrieIntField"/>
</fields>
<uniqueKey>name</uniqueKey>
</schema>

带空格的字符串的完美匹配 cqlsh：试验＆gt; SELECT * FROM test1 WHERE solr_query ='{“q”：“address：\”123 california united states \“”}';

 name  | address                      | age | solr_query
-------+------------------------------+-----+------------
 test1 | 123 california united states |  21 |       null

但如果我想搜索以“123”开头的字符串（带空格的字符串的正则表达式），则会失败。（尝试了其他solr query: {"q":"address:\"123\"*"})

cqlsh:test> SELECT * FROM test1 WHERE solr_query='{"q":"address:\"123\""}';

 name | address | age | solr_query
------+---------+-----+------------

(0 rows)

有没有办法在带有空格的solr字符串字段类型上完成正则表达式？

Answer 1

尝试SELECT * FROM test1 WHERE solr_query='{"q":"address:123*"}';您删除了引号，因为您不再需要完全匹配。

带有空格的DSE Cassandra SOLR查询

1 个答案: