Question

我在控制台里什么都没有。它应该改变包含html到openweatherapp从这个邮政编码获取的信息（我检查这个zip并且它存在并且函数updateByZip创建了良好的链接）。第一个代码是JS和第二个HTML。 JS

var temp;
var loc;
var humidity;
var icon;

function bg() {
  var backs = ["http://wallpapercave.com/wp/JthAGYd.jpg", "http://www.desktopwallpaperhd.net/wallpapers/20/b/welshdragon-landscapes-cometh-background-204971.jpg", "http://s1.picswalls.com/wallpapers/2014/08/08/scottish-landscape-desktop-backgrounds_015751372_152.jpg", "http://img.wallpaperfolder.com/f/4313075B95B2/amazing-winter-backgrounds-6770538-landscape.jpg"];
  var ran = Math.floor(Math.random() * (backs.length));
  $('body').css("background-image", "url('" + backs[ran] + "')")
    //document.body.style.background = "url/'('" + backs[0] + "') no-repeat";
}

function tempCF() {
  var x = document.getElementById("temp").innerHTML;
  var y = document.getElementById("CF").innerHTML;
  x = parseInt(x);
  if (y == "C") {
    x = Math.floor((9 / 5 * x + 32));
    document.getElementById("temp").innerHTML = x;
    document.getElementById("CF").innerHTML = "F"
  } else if (y == "F") {
    x = Math.floor((x - 32) * 5 / 9);
    document.getElementById("temp").innerHTML = x;
    document.getElementById("CF").innerHTML = "C";
  };
}

function updateByZip(zip) {
  var APPID = "55e568aa04114cdf3dc4b90c9ae0a60c";
  var url = "api.openweathermap.org/data/2.5/weather?zip=" + zip + "&APPID=" + APPID;
  sendRequest(url);
}

function sendRequest(url) {
  var xmlhttp = new XMLHttpRequest();
  xmlhttp.onreadystatechange = function() {
    if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
      var data = JSON.parse(xmlhttp.responseText);
      var weather = {};
      weather.temp = data.main.temp;
      weather.humidity = data.main.pressure;
      weather.loc = data.name;
      //weather.icon = data.weather[0].id;
      update(weather);
    }
  };
  xmlhttp.open("GET", url, true);
  xmlhttp.send();
}

function update(weather) {
  document.getElementById("temp").innerHTML = weather.temp;
  document.getElementById("humidity").innerHTML = weather.humidity;
  document.getElementById("loc").innerHTML = weather.loc;
  //document.getElementById("icon").innerHTML = weather.icon;  
};
window.onload = function() {
  var temp = document.getElementById("temp").innerHTML;
  var loc = document.getElementById("loc").innerHTML;
  var humidity = document.getElementById("humidity").innerHTML;
  //var icon = document.getElementById("icon").innerHTML;
  updateByZip(94040);
  //weather.icon = "https://cdn1.iconfinder.com/data/icons/hawcons/32/700175-icon-1-cloud-128.png";
};

HTML

<head>
  <link href="https://fonts.googleapis.com/css?family=Poiret+One" rel="stylesheet">
</head>

<body onclick="bg()">
  <div class="container-fluid">
    <div class="wrapper">
      <div class="row">
        <div class="title"><span id="loc"> Your location</span></div>
      </div>

      <div class="row">
        <div class="col-ms-4">
          <div class="fircol"><span id="temp">0</span>&deg;<span onclick="tempCF()" id="CF">C</span></div>
        </div>
        <div class="col-ms-4">
          <div class="seccol"><span id="humidity">Rain</span></div>
        </div>
        <div class="col-ms-4">
          <div class="thicol"><span class="icon"><img src= https://cdn1.iconfinder.com/data/icons/hawcons/32/700175-icon-1-cloud-128.png></img></span></div>
        </div>
      </div>
    </div>
  </div>
</body>

Answer 1

您的API网址不正确。你应该写：

var url = "http://api.openweathermap.org/data/2.5/weather?zip=" + zip + "&APPID=" + APPID;

天气应用程序Javascript不起作用

1 个答案: