列出预订时出现的日期,只有红色 已使用COUNT聚合函数保留了船只。 这是表
仆人表:
sname rating
Joe 4
Bob 2
Tim 9
Mike 1
Lewis 5
船桌:
bname color rating
Ace orange 6
Bethany red 5
Cruiser green 9
WindySea red 8
预订表:
sname bname day
Bob Ace Monday
Bob Bethany Wednesday
Bob WindySea Saturday
Tim Ace Sunday
Tim Bethany Wednesday
Tim Cruiser Wednesday
Mike Ace Monday
答案 0 :(得分:1)
SELECT r.day
FROM reservation r
JOIN boat b
ON r.bname = b.bname
GROUP BY r.day
HAVING COUNT(CASE WHEN b.color <> 'red' THEN 1 ELSE NULL END) = 0
AND COUNT(CASE WHEN b.color = 'red' THEN 1 ELSE NULL END) > 0 -- optional