Question

<html>
<tr id="userman-orgchart-tree-node-9" class="fancytree-expanded fancytree-folder fancytree-has-children fancytree-exp-e fancytree-ico-ef">
<td>
<span class="fancytree-node" style="padding-left: 16px;">
<span class="fancytree-expander"></span>
<span class="fancytree-icon"></span>
<span class="fancytree-title">Legal</span>
</span>
</tr>
<tr id="userman-orgchart-tree-node-10" class="fancytree-active fancytree-folder fancytree-has-children fancytree-exp-c fancytree-ico-cf">
<td>
<span class="fancytree-node" style="padding-left: 16px;">
<span class="fancytree-expander"></span>
<span class="fancytree-icon"></span>
<span class="fancytree-title">Branch Performance Test</span>
</span>
</tr>
</html>

在这种情况下，在上述情况下，我如何编写元素定位器来确定分支性能测试的范围，同时考虑到 tr id 可以动态地保持更改为 11或12 通过在。之间添加另一条记录。

Answer 1

//span[@class='fancytree-title' and text()='Branch Performance Test']/ancestor::span

以上将返回条件

的跨度的所有跨度祖先

OR

//span[@class='fancytree-title' and text()='Branch Performance Test']/parent::span

以上将返回条件

的跨度的第一个跨越父级

如何找到只有一个属性且与网页中的其他元素重复的元素？

1 个答案: