我想为左连接产生的所有列添加前缀。
当正在连接的两个表之间的名称相同时, left_join()
可以添加后缀。但是,即使它们没有相同的名称,也没有选择始终添加此后缀。而且它没有选择添加前缀。
library(dplyr)
library(nycflights13)
flights2 <- flights %>% select(year:day, hour, origin, dest, tailnum, carrier)
airports2 <- airports
result <- flights2 %>% left_join(airports2, c("dest" = "faa")) %>% head()
结果:
Source: local data frame [6 x 14]
year month day hour origin dest tailnum carrier name
(int) (int) (int) (dbl) (chr) (chr) (chr) (chr) (chr)
1 2013 1 1 5 EWR IAH N14228 UA George Bush Intercontinental
2 2013 1 1 5 LGA IAH N24211 UA George Bush Intercontinental
3 2013 1 1 5 JFK MIA N619AA AA Miami Intl
4 2013 1 1 5 JFK BQN N804JB B6 NA
5 2013 1 1 5 LGA ATL N668DN DL Hartsfield Jackson Atlanta Intl
6 2013 1 1 5 EWR ORD N39463 UA Chicago Ohare Intl
Variables not shown: lat (dbl), lon (dbl), alt (int), tz (dbl), dst (chr)
在这里,只能从连接结果中知道每列的原始表格。
添加此前缀的目的是从表名和从关系数据库加载的数据的列名可靠地计算列名。例如,将使用加载到R
和存储在mySQL
中的数据库结构以及关系数据库的命名约定来标识主键和外键。然后,这些将用于设置连接以及稍后从连接结果中检索数据。
我发现了R
的类似问题,但# add prefix before joining:
names(flights2) <- paste0("flights2.", names(flights2) )
names(airports2) <- paste0("airports2.", names(airports2) )
# in join, use names with prefixes
result <- flights2 %>% left_join(airports2, c("flights2.dest" = "airports2.faa") ) %>% head()
没有:
In a join, how to prefix all column names with the table it came from
答案 0 :(得分:4)
实现此目的的一种简单方法是在执行连接之前将前缀添加到原始表中:
Source: local data frame [6 x 14]
flights2.year flights2.month flights2.day flights2.hour flights2.origin flights2.dest
(int) (int) (int) (dbl) (chr) (chr)
1 2013 1 1 5 EWR IAH
2 2013 1 1 5 LGA IAH
3 2013 1 1 5 JFK MIA
4 2013 1 1 5 JFK BQN
5 2013 1 1 5 LGA ATL
6 2013 1 1 5 EWR ORD
Variables not shown: flights2.tailnum (chr), flights2.carrier (chr), airports2.name (chr),
airports2.lat (dbl), airports2.lon (dbl), airports2.alt (int), airports2.tz (dbl),
airports2.dst (chr)
结果:
tableName.columnName
现在,可以通过以下方式轻松引用已连接的数据框:.children("option").length
答案 1 :(得分:0)
相似的答案,但后缀为一:
library(dplyr)
(band_members
%>% rename_all( funs(paste0(., ".left")))
%>% left_join(band_instruments, by = c("name.left"="name"))
%>% rename_at( .vars = vars(-ends_with(".left")),funs(paste0(., ".right")))
)
或
(band_members
%>% rename_all( funs(paste0(., ".left")))
%>% left_join(
band_instruments%>% rename_all( funs(paste0(., ".right"))),
by = c("name.left"="name.right"))
)
两个都给
# A tibble: 3 x 3
name.left band.left plays.right
<chr> <chr> <chr>
1 Mick Stones <NA>
2 John Beatles guitar
3 Paul Beatles bass