Question

例如，我想从行号20056读取文本文件，直到第1159450行，并将其输出到输出窗口，但我不知道如何操作，因为方法line.readline()从第一行开始。

这是我的代码：

String line;
int currentLineNo = 1;
int startLine = 20056;//40930;
int endLine = 1159450;

FileReader file = new FileReader("yourfilepath");
BufferedReader reader = new BufferedReader(file);

PrintWriter writer = new PrintWriter("yourfilepath", "UTF-8");

while (currentLineNo < startLine) {
    currentLineNo++;
}

while(currentLineNo >= startLine && currentLineNo <= endLine) {
    // System.out.println(currentLineNo);
    line = reader.readLine();

    System.out.println(line);
    // writer.println(line);
    currentLineNo++;
}

reader.close();
writer.close();

如何仅从第20056行打印到第1159450行并将其输出到输出窗口？

Answer 1

String line;
int currentLineNo = 1;
int startLine = 20056;//40930;
int endLine = 1159450;

FileReader file = new FileReader("yourfilepath");
BufferedReader reader = new BufferedReader(file);

PrintWriter writer = new PrintWriter("yourfilepath", "UTF-8");

while (currentLineNo <= endLine)
{
    line = reader.readLine();
    if(currentLineNo >= startLine && currentLineNo<=endLine) 
    {  System.out.println(line); }

    currentLineNo++;
}

reader.close();
writer.close();

Answer 2

（代表OP发布解决方案）。

我只需要删除第一个while循环。

String line;
    int currentLineNo = 1;
    int startLine = 20056;//40930;
    int endLine = 1159450;

    FileReader file = new FileReader("yourfilepath");
    BufferedReader reader = new BufferedReader(file);

    PrintWriter writer = new PrintWriter("yourfilepath", "UTF-8");

    while(currentLineNo<=endLine) 
    {
        line = reader.readLine();
        if(currentLineNo >= startLine && currentLineNo<=endLine) 
        {  System.out.println(line); }

        currentLineNo++;
    }

    reader.close();
    writer.close();

归功于Jay Hamilton。

如何读取某一行直到某一行？

2 个答案: