Question

我正在尝试通过改造发送一个图像和一些字符串，但它不起作用，我总是得到400.我的应用程序已经使用GET或POST等Web服务而没有麻烦，我认为我的问题是上传...

我使用了explanations和改造的github。

我的想法是创建一个新的Dish并将其发送到我的服务器，因此大部分数据来自InputTextField，照片由相机使用Intent拍摄

首先我的上传界面

@Multipart
@POST("japronto/api/chef/dish/new")
Call<Dish> upload(@Part("name") RequestBody name, @Part("description") RequestBody description,@Part("disponibility") RequestBody disp,@Part("max") RequestBody max,@Part("price") RequestBody price, @Part MultipartBody.Part file);

我的上传功能

    public void onOK(){

    RequestBody name = RequestBody.create( MediaType.parse("multipart/form-data"), this.name.getText().toString());
    RequestBody description =
            RequestBody.create(
                    MediaType.parse("multipart/form-data"), this.description.getText().toString());
    RequestBody disp =
            RequestBody.create(
                    MediaType.parse("multipart/form-data"), Integer.toString(this.TorF));

    RequestBody max =
            RequestBody.create(
                    MediaType.parse("multipart/form-data"), this.max.getText().toString());

    RequestBody price =
            RequestBody.create(
                    MediaType.parse("multipart/form-data"), this.price.getText().toString());


    File nImg = new File(folderImg, imgName);

    RequestBody rqFile =
            RequestBody.create(MediaType.parse("multipart/form-data"), nImg);

    MultipartBody.Part body =
            MultipartBody.Part.createFormData("picture", nImg.getName(), rqFile);

    ApiService apiService = ApiManager.createService(ApiService.class, this.chef.getPseudo(), this.chef.getPassword());
    Call<Dish> call = apiService.upload(name, description, disp, max, price, body);
    call.enqueue(new Callback<Dish>() {
        @Override
        public void onResponse(Call<Dish> call, Response<Dish> response) {
            Dish d = response.body();
            Log.d(TAG, "onResponse: "+d.getName());
        }

        @Override
        public void onFailure(Call<Dish> call, Throwable t) {

        }
    });

}

我在服务器上的视图

    @app.route('/japronto/api/chef/dish/new', methods=['POST'])
    def upload():
    if request.method == 'POST':
     if 'file' not in request.files:
        print 'pbs'
    file = request.files['file']

    if file and allowed_file(file.filename):
        filename = secure_filename(file.filename)
        print filename
        file.save(os.path.join(app.config['UPLOAD_FOLDER'], filename))
        return {'name':filename}
return{'name':'erro'}

有什么想法吗？

Answer 1

试试这个

@Multipart
@POST("japronto/api/chef/dish/new")
Call<Dish> upload(@Part("name") RequestBody name, @Part("description") RequestBody description,@Part("disponibility") RequestBody disp,@Part("max") RequestBody max,@Part("price") RequestBody price, @Part("ImageNameHere\"; filename=\"image.png\" ") RequestBody image);



File nImg = new File(folderImg, imgName);
RequestBody rqFile = RequestBody.create(MediaType.parse("image/png"), nImg);

检查这些链接

Link 1 Link 2 Link 3

Android Retrofit 2 multipart总是给出错误400

1 个答案: