Question

我正在创建一个包含大量对象的JSON数组，例如：

var JSON = [];
var obj1 = {
    "familyId": 5,
    "implant": [{
        "reference": 12345678,
        "quantity": 3,
        "origin": "ours",
        "lot": null
        }]
    }
var obj2 = {
    "familyId": 5,
    "implant": [{
        "reference": 12345678,
        "quantity": 2,
        "origin": "theirs",
        "lot": null
        }]
    }
JSON.push(obj1);
JSON.push(obj2);

如何搜索此JSON数组（使用可能find()或indexOf()）来确定原产地为“我们的”的参考数量“12345678”？

Answer 1

您可以使用Array#find作为外部数组，使用Array#some作为内部数组的搜索条件。

＆＃13;

var array = [{ "familyId": 5, "implant": [{ "reference": 12345678, "quantity": 3, "origin": "ours", "lot": null }] }, { "familyId": 5, "implant": [{ "reference": 12345678, "quantity": 2, "origin": "theirs", "lot": null }] }],
    object = array.find(o => o.implant.some(a => a.reference === 12345678 && a.origin === 'ours'));

console.log(object);

＆＃13;

Answer 2

你可以循环throgh JSON数组并列出它们 - 演示如下：

＆＃13;

var JSON = [];
var obj1 = {
    "familyId": 5,
    "implant": [{
        "reference": 12345678,
        "quantity": 3,
        "origin": "ours",
        "lot": null
        }]
    }
var obj2 = {
    "familyId": 5,
    "implant": [{
        "reference": 12345678,
        "quantity": 2,
        "origin": "theirs",
        "lot": null
        }]
    }
JSON.push(obj1);
JSON.push(obj2);

function search(reference, origin) {
  var found = [];
   JSON.forEach(function(element) {
     element.implant.forEach(function(ele){
         if(ele.reference == reference && ele.origin == origin) {
            this.push(element);
         }
     }, this);
   
   }, found);
  return found;
}

console.log(search(12345678, "ours"));

＆＃13;

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＆＃13;

在JSON对象中查找

2 个答案: