我想在sendbird api中使用sendFileMessage
。它需要文件值,我想使用drawable
(或assets
)中的此文件。 sendBird API
这是来自sendbird的剪切代码
Hashtable<String, Object> info = Helper.getFileInfo(getActivity(), uri);
final String path = (String) info.get("path");
File file = new File(path);
String name = file.getName();
String mime = (String) info.get("mime");
int size = (Integer) info.get("size");
sendFileMessage(file, name, mime, size, "", new BaseChannel.SendFileMessageHandler() {
public void onSent(FileMessage fileMessage, SendBirdException e) {
if (e != null) {
return;
}
mAdapter.appendMessage(fileMessage);
mAdapter.notifyDataSetChanged();
}
});
此代码运行良好,我从开放图像意图获得uri
。但我想用于其他目的,我想替换此代码
File file = new File(path);
变得像
File file = new File(<path or uri from drawable or assets>);
我尝试了uri
Uri uri = Uri.parse("android.resource://com.package.name/raw/filenameWithoutExtension");
File file = new File(uri.getPath());
使用inputStream
try {
File f=new File("file name");
InputStream inputStream = getResources().openRawResource(R.raw.myrawfile);
OutputStream out=new FileOutputStream(f);
byte buf[]=new byte[1024];
int len;
while((len=inputStream.read(buf))>0)
out.write(buf,0,len);
out.close();
inputStream.close();
}
catch (IOException e){}
始终无法获取文件并返回错误代码ERR_REQUEST_FAILED 800220
答案 0 :(得分:0)
您是否尝试过如下?
String fileName = FILE_NAME;
File cachedFile = new File(this.getActivity().getCacheDir(), fileName);
try {
InputStream is = getResources().openRawResource(R.raw.sendbird_ic_launcher);
FileOutputStream fos = new FileOutputStream(cachedFile);
byte buf[] = new byte[1024];
int len;
while ((len = is.read(buf)) > 0)
fos.write(buf, 0, len);
fos.close();
is.close();
} catch (IOException e) {
e.printStackTrace();
}
groupChannel.sendFileMessage(cachedFile, fileName, "image/jpg", (int) cachedFile.length(), "", new BaseChannel.SendFileMessageHandler() {
@Override
public void onSent(FileMessage fileMessage, SendBirdException e) {
}
});
这适合我。