不支持的字段：将即时格式化为日期ISO时的年份

Question

我正在尝试将Instant格式化为ldap日期ISO8601，但它在f.format（Instant.now（））失败; ：

String input = "20161012235959.0Z";
DateTimeFormatter f = DateTimeFormatter.ofPattern ( "uuuuMMddHHmmss[,S][.S]X" );
OffsetDateTime odt = OffsetDateTime.parse ( input , f );
Instant instant = odt.toInstant ();

f.format(Instant.now());

错误是：

java.time.temporal.UnsupportedTemporalTypeException: Unsupported field: Year

    at java.time.Instant.getLong(Instant.java:603)
    at java.time.format.DateTimePrintContext.getValue(DateTimePrintContext.java:298)
    at java.time.format.DateTimeFormatterBuilder$NumberPrinterParser.format(DateTimeFormatterBuilder.java:2540)
    at java.time.format.DateTimeFormatterBuilder$CompositePrinterParser.format(DateTimeFormatterBuilder.java:2179)
    at java.time.format.DateTimeFormatter.formatTo(DateTimeFormatter.java:1746)
    at java.time.format.DateTimeFormatter.format(DateTimeFormatter.java:1720)
...
...

Answer 1

要格式化即时，需要时区。

 String input = "20161012235959.0Z";
 DateTimeFormatter f = DateTimeFormatter
       .ofPattern ( "uuuuMMddHHmmss.SX" ) 
       .withLocale( Locale.FRANCE )
       .withZone( ZoneId.of("UTC"));
 OffsetDateTime odt = OffsetDateTime.parse ( input , f );
 Instant instant = odt.toInstant ();

 System.out.println(input);
 System.out.print(f.format(instant));