Question

在以下脚本中，如何在Assets文件夹中获取脚本的路径？

using UnityEngine;
using System.Reflection;
using System.IO;
using UnityEditor;

[InitializeOnLoad]
public class MyWindow : ScriptableObject
{
    static string pathToScript;

    [MenuItem("Window/My Window")]
    static void Open()
    {
        // Do something with `pathToScript`
    }

    // This function is NOT called when the object is loaded.
    protected void OnEnable()
    {
        var script = MonoScript.FromScriptableObject( this );
        pathToScript = AssetDatabase.GetAssetPath( script );
    }
}

问题是OnEnabled它没有被调用，似乎获取脚本路径的唯一方法是通过AssetDatabase.GetAssetPath，这需要一个实例。

Unity中的版本是5.5.0b3。

Answer 1

要在继承OnEnable()时调用ScriptableObject函数，您必须从CreateInstance()类调用ScriptableObject函数。

[InitializeOnLoad]
public class MyWindow : ScriptableObject
{
    static string pathToScript;
    static MyWindow windowInstance;

    [MenuItem("Window/My Window")]
    static void Open()
    {
        Debug.Log("Open:" + pathToScript);

        //Do something with `pathToScript`

        if (windowInstance == null)
            windowInstance = ScriptableObject.CreateInstance<MyWindow>();

    }

    protected void OnEnable()
    {
        Debug.Log("Enabled!");
        var script = MonoScript.FromScriptableObject(this);
        pathToScript = AssetDatabase.GetAssetPath(script);
    }
}

使用ScriptableObject.CreateInstance的另一种方法是从另一个脚本调用它。

[InitializeOnLoad]
public class MyWindow : ScriptableObject
{
    static string pathToScript;

    [MenuItem("Window/My Window")]
    static void Open()
    {
        Debug.Log("Open:" + pathToScript);

        //Do something with `pathToScript`
    }

    protected void OnEnable()
    {
        Debug.Log("Enabled!");
        var script = MonoScript.FromScriptableObject(this);
        pathToScript = AssetDatabase.GetAssetPath(script);
    }
}

<强>测试：

public class Test : MonoBehaviour
{
    public MyWindow myWindow;
    public void OnEnable()
    {
        if (myWindow == null)
            myWindow = Object.FindObjectOfType<MyWindow>();

        if (myWindow == null)
            myWindow = ScriptableObject.CreateInstance<MyWindow>();
    }
}

未调用ScriptableObject的OnEnable函数

1 个答案: