Question

如何使用switch case来保存来自许多实体的实体我使用变量来依赖实体这段代码可能会帮助你理解我的问题??

public function addAction($name, Request $request) {
    switch ($name) {
        case 'Article':
            $name = new Article();
            $nameType = new ArticleType();
            break;
       case 'Comment':
            $name = new Comment();
            $nameType = new CommentType();
            break;
       case 'Blog':
            $name = new Blog();
            $nameType = new BlogType();
            break;

         return $name;
         return $nameType;
    }

    $form = $this->get('form.factory')->create($nameType, $name);
    $em = $this->getDoctrine()->getManager();
    $em->persist($name);
    $em->flush();

    return $this->render('WFBundle:Blog:add.html.twig', array(
        'form' => $form->createView(),
    ));
}

Answer 1

Switch Case不是一个函数，在此代码下面使用

public function addAction($name, Request $request) {
switch ($name) {
case 'Article':
    $name = new Article();
    $nameType = new ArticleType();
    break;
   case 'Comment':
    $name = new Comment();
    $nameType = new CommentType();
    break;
case 'Blog':
    $name = new Blog();
    $nameType = new BlogType();
    break;
}
$form = $this->get('form.factory')->create($nameType, $name);
$form->handleRequest($request);
if($form->isSubmitted()){
    $em = $this->getDoctrine()->getManager();
    $em->persist($name);
    $em->flush();
}
return $this->render('WFBundle:Blog:add.html.twig', array(
  'form' => $form->createView(),
));
}

所以不要使用返回行，只返回控制器返回

在symfony2中切换案例实体

1 个答案: