脚本中的最终命令（sed命令）不起作用

Question

我这里有一个脚本文件，名为editfile.script：

#!/bin/bash

sed '{
1i \Game Commence\nAre You Ready???\ 
s/game/Game/g
s/points/Points/g
s/the\sthe/the/g 
/^ *$/d
$a It's time
}' "$1"

编辑名为GameOverview

的文件

This game will begin in 3 minutes.
The objective is to score 10 points.
If you score 10 points, u move to the the next round

Good luck, may the the force b w u

现在当我运行.\editfile.script GameOverview（来自C shell）命令行时，我收到了这个输出：

Game Commence 
Are You Ready???
This Game will begin in 3 minutes.
The objective is to score 10 Points.
If you score 10 points, u move to the next round
Good luck, may the force b w u

正如您所看到的，每个命令都已执行：除以外的附加命令$a It's time。为什么会发生这种情况，以及如何解决？而且我认为它与前面的＆＃34;删除所有空白行＆＃34;有关。命令/^ *$/d，因为当我摆脱它时，＆＃34;它的时间＆＃34;附上：

Game Commence 
Are You Ready???
This Game will begin in 3 minutes.
The objective is to score 10 Points.
If you score 10 points, u move to the next round

Good luck, may the force b w u
It's time

Answer 1

问题是您要追加的字符串中的单引号It's time。它结束了你的sed命令的开头单引号。

您可以通过结束第一个引号获得单引号，将单引号放在双引号之间，然后启动另一个单引号字符串：

$a It'"'"'s time

要完全避免这个问题，您可以将sed命令放入单独的文件中，而不是将其包装在shell脚本中：

$ cat sedscr.sed
1i\
Game Commence\nAre You Ready???
s/game/Game/g
s/points/Points/g
s/the\sthe/the/g
/^ *$/d
$a\
It's time

我还将i和a命令分成两行，这应该是发布这些命令的最便携方式。

然后你可以这样称呼它：

$ sed -f sedscr.sed GameOverview
Game Commence
Are You Ready???
This Game will begin in 3 minutes.
The objective is to score 10 Points.
If you score 10 Points, u move to the next round
Good luck, may the force b w u
It's time

像这样，你不必特别对待单引号。