Question

我正在使用MySQL表格内容创建表格。问题是我正在尝试为表中的每一行创建一个删除（x）按钮（删除列）。

 <?php
$html = "<table>";
$html .= "<tr>";
$html .= "<th>id</th>";
$html .= "<th>Event type</th>";
$html .= "<th>Date</th>";
$html .= "<th>Price(€)</th>";
$html .= "<th>Description</th>";
$html .= "<th>Delete</th>";
$html .= "</tr>";

foreach($event as $e){
    $html .= "<tr>";
    $html .= "<td>$e->eventId</td>";
    $html .= "<td>$e->eventType</td>";
    $html .= "<td>$e->eventDate</td>";
    $html .= "<td>$e->eventPrice</td>";
    $html .= "<td>$e->eventDescr</td>";
    $html .= "<td><--the delete button has to be here--></td>";
    $html .= "</tr>";
}

$html .= "</table>";
echo $html;

我尝试使用onclick按钮，但绝对失败了。任何人都可以给我任何提示吗？

Answer 1

我的解决方案只是众多可能的解决方案之一

1）创建js函数以删除行并调用ajax请求以从DB中删除项目

function removeRow(item,eventId)
{
  var row = $(item).parent().parent();
  $.ajax(url: '(url_to)/remove.php?id='+eventId,
         success: function(resp)
         {
           if(resp=='OK')
           {
             row.remove();
           }
         }
  );

}

2）创建按钮

$html .= '<td><a href="javascript:removeRow(this,'.$e->eventId.');return false;">Delete</a></td>';

3）创建PHP脚本

<?php
//connection to DB
$dbhost = "localhost";
$dbname = "dbb";
$dbuser = " ";
$dbpswd = " ";

try
{
  $db = new PDO("mysql:host=".$dbhost.";dbname=".$dbname,$dbuser,$dbpswd);
  $db->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);

  //removing event
  $count = $db->exec("DELETE FROM `someTable` WHERE id = {intval($id)}");
  //return OK if event was correctly deleted
  if($count==1)
  {
    echo 'OK';
  }
}
catch (PDOException $e)
{
  //only for development version
  echo $e->getMessage();
}
die();

按ID从MySQL中删除一行

1 个答案: