Question

我想声明并隐藏一些关于活动的观点，但它太复杂并且耗费了大量时间。我可以用循环或其他东西来做这件事吗？

//Startup
    //Hide msgs
    CardView msgUser1v = (CardView) findViewById(R.id.msgUser1v);
    msgUser1v.setVisibility(View.GONE);
    CardView msgBot1v = (CardView) findViewById(R.id.msgBot1v);
    msgBot1v.setVisibility(View.GONE);
    CardView msgUser2v = (CardView) findViewById(R.id.msgUser2v);
    msgUser2v.setVisibility(View.GONE);
    CardView msgBot2v = (CardView) findViewById(R.id.msgBot2v);
    msgBot2v.setVisibility(View.GONE);
    CardView msgUser3v = (CardView) findViewById(R.id.msgUser3v);
    msgUser3v.setVisibility(View.GONE);
    CardView msgBot3v = (CardView) findViewById(R.id.msgBot3v);
    msgBot3v.setVisibility(View.GONE);
    CardView msgUser4v = (CardView) findViewById(R.id.msgUser4v);
    msgUser4v.setVisibility(View.GONE);
    CardView msgBot4v = (CardView) findViewById(R.id.msgBot4v);
    msgBot4v.setVisibility(View.GONE);
    CardView msgUser5v = (CardView) findViewById(R.id.msgUser5v);
    msgUser5v.setVisibility(View.GONE);
    CardView msgBot5v = (CardView) findViewById(R.id.msgBot5v);
    msgBot5v.setVisibility(View.GONE);

Answer 1

我认为这是一个很好的方法：

List<CardView> cards = new ArrayList<CardView>();
for (int i = 1 ; i <= cardsCount ; i++)
{
    int id = getResources().getIdentifier("msgBot"+i+"v", "id", context.getPackageName());
    cards.add((CardView) findViewById(id));
}

现在您拥有卡阵列中的所有卡片视图。如果你想让它们看不见，你可以这样轻松地做到：

for(CardView c : cards){
    c.setVisibility(View.INVISIBLE);
}

Answer 2

如果您的卡片视图位于某个容器（如相对布局）下，那么您可以遍历子项。

int childs = relativeLayout.getChildCount(); 
for(int i=0; i<childs; i++){
    View child = relativeLayout.getChildAt(i);
     if(child instanceOf CardView){
             child.setVisibility(View.GONE);
     }
}

您可以进一步放置更多条件检查以排除某些卡片视图。

如果CardViews只是容器中的项目，并且您想要隐藏所有这些项目，那么yoi可以简单地设置父布局的可见性。

relativeLayout.setVisibility(View.GONE);

声明具有相似名称的多个视图（Android Studio）

2 个答案: