Question

我对我创建的MySql查询感到困惑。运行代码时，查询无法将数据插入数据库。我想弄清楚发生了什么。当我尝试在我的localhost上运行它时，没有发现错误，插入了查询..我使用的是PHP 5.6，我的Web服务器也使用PHP 5.6。

<?php 
    include 'koneksi.php';
    $user = $_POST['username'];
    $pass = $_POST['password'];
    $nama = $_POST['nama'];
    $mail = $_POST['email'];
    $tlp  = $_POST['telp'];
    $date = date("j F Y");
    $invoice = mt_rand(100000, 999999);
    if ($_POST['pack'] === 'Basic') {
        $pack_name = 'Basic Pack';
        $price = '$5';
        $permiti = 'basic';
        $limit = '15';
    } elseif ($_POST['pack'] === 'Premium') {
        $pack_name = 'Premium Pack';
        $price = '$10';
        $permiti = 'premium';
        $limit = '20';
    } elseif ($_POST['pack'] === 'Pro') {
        $pack_name = 'Pro Pack';
        $price = '$15';
        $permiti = 'pro';
        $limit = '25';
    } elseif ($_POST['pack'] === 'Ultimate') {
        $pack_name = 'Ultimate Pack';
        $price = '$20';
        $permiti = 'ultimate';
        $limit = '99';
    } else {

    }
    $permit = 'member';
    $start = date("md");
    $end = date("md", strtotime(date("md", strtotime($start)). " + 30 day"));
    $start_date = date("j F Y");
    $end_date = date("j F Y", strtotime(date("j F Y", strtotime($start_date)). " + 30 day"));

    $encrypts = md5($nama);

        $check = mysql_query("SELECT * FROM user WHERE username = '$user'");
    if(mysql_num_rows($check) <> 0 ){
        header("location:register.php?message=fail");
    } else {
        if(!$user || !$pass || !$mail || !$nama || !$tlp){
            echo 'Terdapat data yang kosong<br/>';
            echo '<a href="register.php">Back</a>';
        } else {
            $save = mysql_query("INSERT INTO user VALUES('', '$nama', '$user', '$pass', '$date', '$mail', '$tlp', '$permit')");
            $gets = mysql_query("INSERT INTO user_pack VALUES('', '$pack_name', '$user', '$start', '$end', '0', '$limit', '$price', '$permiti', '$encrypts', '$invoice', '$start_date', '$end_date', '0')");
            if($save || $gets){
                session_start();
                $_SESSION['username'] = $user;
                $_SESSION['status'] = 'login';
                header("location:user/invoice.php");

            } else {
                header("location:register_pack.php?message=fail1");
            }   
        }
    }

?>

请帮帮我:(

Answer 1

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/js/bootstrap.min.js"></script>
<link href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css" rel="stylesheet"/>

<button type="button" class="btn btn-info btn-lg" data-toggle="modal" data-target="#myModal">Open Modal</button>

<!-- Modal -->
<div id="myModal" class="modal fade" role="dialog">
  <div class="modal-dialog">

    <!-- Modal content-->
    <div class="modal-content">
      <div class="modal-header">
        <button type="button" class="close" data-dismiss="modal">&times;</button>
        <h4 class="modal-title">Modal Header</h4>
      </div>
      <div class="modal-body">
        <p>Some text in the modal.</p>
      </div>
      <div class="modal-footer">
        <button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
      </div>
    </div>

  </div>
</div>

SQL不会插入数据库

1 个答案: