我需要在点击删除按钮时找到每个范围内的值。任何帮助都应该被赞赏。当我点击删除链接时,我需要返回raw.proample中的用户名,项目名和模块。例如,当我点击mysqlclient附近的删除按钮时,我需要aasttest,mysite和mysql客户端作为输出。
<html>
<head>
</head>
<body>
<?php require_once 'cms_class.php';
$dj = new DCMSI();?>
<?php
$modules = $dj->view_user_modules(); ?>
<?php if(!$modules):?>
<?php echo ""; ?>
<?php else:?>
<h3>user modules</h3>
<table border='1'>
<tr><th>module</th><th>project</th><th colspan="2">module</th></tr>
<?foreach ($modules as $key =>$value):?>
<tr class="delete-module"><td class="username"><?php echo $value['username'];?></td>
<td class="project"><?php echo $value['project'];?></td>
<td><?foreach ($value['modules'] as $key =>$value):?><span class="module"><?php echo $value['module']?></span> <a href="">delete</a></br><?php endforeach; ?></td>
<?php endforeach; ?>
<?php endif;?>
</table>
</body>
</html>
<script src="js/jquery.js"></script>
<script src="js/bootstrap.min.js"></script>
<script src="js/jquery.toaster.js"></script>
<script src="js/bootbox/bootbox.min.js"></script>
<script>
$('.delete-module').off('click').on('click', function(e){
e.preventDefault();
var username = $(this).closest('tr').find('.username').html();
var project = $(this).closest('tr').find('.project').html();
var module = $(this).closest('tr').find('span.module').val();
});
</script>
答案 0 :(得分:1)
更改您的表并添加一个类到锚标记
我添加了课程deldata
<table border='1'>
<tr><th>module</th><th>project</th><th colspan="2">module</th></tr>
<?foreach ($modules as $key =>$value):?>
<tr class="delete-module"><td class="username"><?php echo $value['username'];?></td>
<td class="project"><?php echo $value['project'];?></td>
<td><?foreach ($value['modules'] as $key =>$value):?><span class="module"><?php echo $value['module']?></span> <a href="" class="deldata">delete</a></br><?php endforeach; ?></td>
<?php endforeach; ?>
<?php endif;?>
</table>
<script>
$('.deldata').click(function(e){
e.preventDefault();
var username = $(this).closest('tr').find('.username').text();
var project = $(this).closest('tr').find('.project').text();
var module = $(this).prev().text();
alert(module);
});
</script>
答案 1 :(得分:1)
你可以这样。
$(document).ready(function() {
$("table").on("click", "tr", function(event) {
var obj = {};
obj.raw = $(event.target).siblings("span").html().trim();
obj.module =
$(event.currentTarget).find(".moduleName").html().trim();
obj.project = $(event.currentTarget).find(".projectName").html().trim();
console.log(obj);
});
});
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td,
th {
border: 1px solid black;
}
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<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<table>
<thead>
<tr>
<th>Module</th>
<th>Project</th>
<th>Module</th>
</tr>
</thead>
<tbody>
<tr>
<td class="moduleName">assttest
</td>
<td class="projectName">myssite
</td>
<td>
<div>
<span>mysql</span>
<a href="#">delete</a>
</div>
<div>
<span>django-filter</span>
<a href="#">delete</a>
</div>
</td>
</tr>
<tr>
<td class="moduleName">assttest
</td>
<td class="projectName">newsite</td>
<td>
<div>
<span>Test Module</span>
<a href="#">delete</a>
</div>
</td>
</tr>
</tbody>
</table>
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