Question

我有一张看起来像这样的表：

| user_id | client_application_id | invalidated_at
|       1 | 55555 | |
|       1 | 123   | |

我希望能做一件事：

能够计算有多少user_id在其帐户中拥有超过250个client_application_id并对其进行排序，使其从250开始上升。

我当前（不正确）的查询如下所示：

select  user_id, count(user_id) as cnt from tokens where invalidated_at is null group by user_id having count(user_id) > 250 order by cnt ;

输出如下：

  user_id   | cnt 
------------+-----
    1 | 251
    5 | 251

使用这个例子，我希望查询计算具有251的两个用户，所以它看起来像这样：

Count_Of_Users  | Application_Count
2 | 251

Answer 1

您可以使用与查询类似的内容作为子查询，并获得所需的输出：

    select count(user_id) as count_of_users, cnt as application_count from
    (
       select  user_id, count(client_application_id) as cnt 
       from tokens 
       where invalidated_at is null 
       group by user_id having count(client_application_id) > 250 
    ) t
    group by cnt
    order by cnt

Answer 2

不清楚secondo查询的预期结果是什么，可能是像这样的问题

  select users.*, t.user_id, t.cnt 
  from users 
  inner join ( 

      select  user_id, count(user_id) as cnt 
      from tokens 
      where invalidated_at is null 
      group by user_id 
      having count(user_id) > 250 
  ) t on users.id = t.user_id 
  order by t.user_id

SQL：帮助在一个查询中执行两个计数

2 个答案: