Question

我们可以使用dateutil pakage计算两个日期之间的年数，月数，天数。在我的代码中，我使用索引来获取年，月和日。但是dateutil包 - ＆＃39; relativedelta＆＃39; object不支持索引。请求帮助计算两个日期之间的年数，月数，天数而不使用包裹。

from datetime import datetime, date, time


class Employee:
        raise_amt = 1.05

        def __init__(self, first, last, pay, birthdate='07-03-1991', joindate='31-12-2013'):
            self.first = first
            self.last = last
            self.pay = int(pay)
            self.birthdate = birthdate #instance variable
            self.joindate = joindate
            self.first = first + "." + last + "@company.com"

        def exeperience(self): #calculating experience
            self.joindate = datetime.strptime(self.joindate, '%d-%m-%Y')
            today = date.today()
            experience = ((today.year-self.joindate.year),(today.month-self.joindate.month),(today.day - self.joindate.day))

            return experience

        @classmethod
        def from_string(cls, emp_str):
            first, last, pay = emp_str.split('-')
            return cls(first, last, pay)


emp_str_1 = 'Nanda-Reddy-45412'

emp_1 = Employee.from_string(emp_str_1)

sync=emp_1.exeperience()
print('Employee experience is{} years {} months {}days:'.format(sync[0],sync[1],sync[2]))

输出：员工经验为3年-2个月-9天：但确切输出应该是2年10个月22天。帮助我得到这个输出

Answer 1

实际上，您无法以相对形式表示日期增量＆＃34; YYYY年，MM月和DD天＆＃34;确切地说，由于每个月的日子不同而且有闰年，你的结果将是模棱两可的。但如果您只是需要一些描述，请参阅以下代码：

def exeperience(self): #calculating experience
    self.joindate = datetime.strptime(self.joindate, '%d-%m-%Y')
    today = date.today()
    days = (today - self.joindate).days
    years, days = days // 365, days % 365
    months, days = days // 30, days % 30
    return (years, months, days)

Answer 2

我已经定义了一个函数daysBetweenDates（year1，month1，day1，year2，month2，day2），它们将提供所需的结果。我还创建了这个主函数中使用的较小的子函数。使用的闰年定义是 - 如果它们是世纪年，可以被4整除，可以被400整除。感谢。

def daysinyear (year):
    if year % 4 == 0:
        days = 366
        if year % 100 == 0 and year % 400 !=0:
            days = 365
            return days
        return days
    days = 365
    return days

def daysbwwholeyears(year1,year2):
    i=year1
    days=0
    while i<=year2:
        days = daysinyear(i) + days
        i=i+1
    return days


def daystodate (month,day,year):
    days = summonth (month - 1,year) + day
    return days

def summonth (month,year):#is mahine ke end tak kitne din ho chuke
    if year % 4 == 0:
        daysinmonth = [31,29,31,30,31,30,31,31,30,31,30,31]
        days = 0
        i=0
        while i< month:
            days = days + daysinmonth[i]
            i=i+1
        return days

    daysinmonth = [31,28,31,30,31,30,31,31,30,31,30,31]
    days = 0
    i=0
    while i< month:
        days = days + daysinmonth[i]
        i=i+1
    return days

def daysBetweenDates(year1, month1, day1, year2, month2, day2):
    if year2 - year1 ==0:
        days = daystodate(month2,day2,year2) - daystodate(month1,day1,year1)
        return days

    if year2 - year1 ==1:
        days = daysinyear(year1) - daystodate(month1,day1,year1) +     daystodate(month2,day2,year2)
        return days


    days = daysbwwholeyears(year1+1,year2-1) + daysinyear(year1) -  daystodate(month1,day1,year1) + daystodate(month2,day2,year2)
    return days

不使用包，如何计算python中两个日期之间的年数，月数，天数

2 个答案: