Question

考虑以下树：

bin\ [directory]
--- file.ext
bin\a [directory]
--- file.bin
--- file2.bin
--- file3.bin
--- anotherDir\ [directory]
-------------- image.png
-------------- image1.png
-------------- image2.png
-------------- image3.png
-------------- image4.png
bin\b [directory]
--- xyz.etc
--- xyz.etc
--- zyx.etc
--- deepDir\ [directory]
-------------- image.tif
-------------- image1.tif
-------------- deepestDir\ [directory]
------------------------- something.exe
------------------------- app.exe

我想要做的是获取（现在打印）最深的可用文件，然后获取其目录名称。

所以请考虑这个最深的目录：

-------------- deepestDir\ [directory]
------------------------- something.exe
------------------------- app.exe

首先，我想打印相对路径：

APP.EXE
something.exe
然后打印包含bin\b\deepDir\deepestDir

在那之后，下一个最深的将是：

--- deepDir\ [directory]
-------------- image.tif
-------------- image1.tif

所以打印：

image.tif
image1.tif
包含在这种情况下为'bin \ b \ deepDir'的目录

[..]等依据主目录.

我已经尝试了几种可能性并最终确定了这一点：

# First, collect ALL files:
SEARCH_PATH = "E:\\project\\elohim\\"

for root, dirs, files in os.walk(SEARCH_PATH):
    for file in files:
        relativePath = os.path.relpath(root, SEARCH_PATH)
        if relativePath == ".":
            relativePath = ""

        print 'File: {}'.format(os.path.join(relativePath, file))

# Then collect DEEPEST subdirectories
subDirs = []
for root, dirs, files in os.walk(SEARCH_PATH):
    subDirs.append(os.path.relpath(root, SEARCH_PATH))

subDirs.sort(lambda x, y: cmp(x.count(os.path.sep), y.count(os.path.sep)), reverse=True)

for k in subDirs:
     print 'Directory: {}'.format(k)

实际上它不是我想要的，但是它真的很接近（它首先搜索目录中的所有文件，然后搜索最深的子目录）。

（所以我现在所拥有的就是这样）：

- image.png
- image1.png
- image2.png
- image3.png
- image4.png
- xyz.etc
- xyz.etc
- zyx.etc
- image.tif
- image1.tif
[..]
and then directories:
bin\b\deepDir\deepestDir
bin\b\deepDir
bin\b
bin

它不够清楚，让我知道，我会尽力解释。

Answer 1

这可能对您有用：

a2 = c(5, 5, 3, 3, 3, 3, 1, 1, 2, 4, 4, 4)

你遍历树两次。没有必要。代码实际上创建了一个元组列表。每个元组包含深度，相对路径和文件名。

之后，列表将被排序为首先包含最深的文件夹。

然后，代码按深度和相对路径对文件进行分组。我使用a3 = c(4, 4, 4, 2, 3, 3, 3, 3, 1, 1, 5, 5)?方法的[Flags] public enum ProcessAccessFlags : uint { All = 0x001F0FFF, Terminate = 0x00000001, CreateThread = 0x00000002, VirtualMemoryOperation = 0x00000008, VirtualMemoryRead = 0x00000010, VirtualMemoryWrite = 0x00000020, DuplicateHandle = 0x00000040, CreateProcess = 0x000000080, SetQuota = 0x00000100, SetInformation = 0x00000200, QueryInformation = 0x00000400, QueryLimitedInformation = 0x00001000, Synchronize = 0x00100000 } public static string GetWindowText(IntPtr ControlHandle, IntPtr ProcessHandle) { int BufferSize = 256; StringBuilder sb = new StringBuilder(BufferSize); byte[] ControlNameByteArray = new byte[BufferSize]; long BytesRead = 0; IntPtr BytesReadPointer = new IntPtr(BytesRead); IntPtr RemoteProcessMemoryAddress = IntPtr.Zero; IntPtr RemoteProcessHandle = IntPtr.Zero; try { uint Message = RegisterWindowMessage("WM_GETCONTROLNAME"); RemoteProcessHandle = OpenProcess(ProcessAccessFlags.CreateThread | ProcessAccessFlags.QueryInformation | ProcessAccessFlags.VirtualMemoryOperation | ProcessAccessFlags.VirtualMemoryWrite | ProcessAccessFlags.VirtualMemoryRead, false, Process.Id); RemoteProcessMemoryAddress = VirtualAllocEx(RemoteProcessHandle, IntPtr.Zero, new IntPtr(sb.Capacity), AllocationType.Commit, MemoryProtection.ExecuteReadWrite); if (RemoteProcessMemoryAddress == IntPtr.Zero) { throw new Exception("GetWindowText: " + GetLastWin32Error()); } SendMessage(ControlHandle, Message, new IntPtr(sb.Capacity), RemoteProcessMemoryAddress); ReadProcessMemory(RemoteProcessHandle, RemoteProcessMemoryAddress, ControlNameByteArray, BufferSize, out BytesReadPointer); string ControlName = Encoding.Unicode.GetString(ControlNameByteArray).TrimEnd('\0'); return ControlName; } finally { VirtualFreeEx(RemoteProcessHandle, RemoteProcessMemoryAddress, BufferSize, FreeType.Release); } }方法。

从那里可以很容易地打印出你喜欢的东西和任何订单。

获取最深的嵌套路径（文件，然后是目录）

1 个答案: