Question

我有一个方法可以创建一组6个对象，并为其分配变量，包括名称，团队，位置等。我需要一种方法，可以搜索对象数组，只显示具有选定变量（位置）的对象。该项目要求我显示只有具有特定位置的玩家的列表。因此，如果所选位置为“QB”，则会显示“Eli Manning”“Tom Brady”“Derek Car”及其统计数据。

//constructor creating 6 players
public NFLPlayerManager(){
    NFLPlayer x = new NFLPlayer("Eli Manning", "New York Giants", "QB", 21, 77, 72, 170, 0, 160, "TCU");
    playerList.add(x);
    NFLPlayer y = new NFLPlayer("Tom Brady", null, "QB", 0, 0, 0, 0, 0, 0, null);
    playerList.add(y);
    NFLPlayer z = new NFLPlayer("Josh Kline", null, null, 0, 0, 0, 0, 0, 0, null);
    playerList.add(z);
    NFLPlayer a = new NFLPlayer("Derek Carr", null, "QB", 0, 0, 0, 0, 0, 0, null);
    playerList.add(a);
    NFLPlayer b = new NFLPlayer("Rob Gronkowski", null, "TE", 0, 0, 0, 0, 0, 0, null);
    playerList.add(b);
    NFLPlayer c = new NFLPlayer("James White", null, null, 0, 0, 0, 0, 0, 0, null);
    playerList.add(c);
}

Answer 1

public void showPlayerByPosition(String position)
{
    for(int i = 0; i < playerList.size(); i++)
    {
        //now lets grab the NFLPlayer's position with a getter and compare it to the given string in our parameter
        if(playerList.get(i).getposition().equals(position))
        {
            //then print the NFLPlayer
            playerList.get(i).showPlayer(); //Note i making up the name for the print function
        }

    }
}

现在您可以像这样调用函数

showPlayerbyPosition("QB")

根据位置

1 个答案: