Question

我正在使用Python API使用以下代码执行带有H2O的GridSearch，

from h2o.estimators.random_forest import H2ORandomForestEstimator
from h2o.grid import H2OGridSearch

hyper_parameters = {'ntrees':[10, 50, 100, 200], 'max_depth':[5, 10, 15, 20, 25], 'balance_classes':[True, False]}

search_criteria = {
    "strategy": "RandomDiscrete",
    "max_runtime_secs": 600,
    "max_models": 30,
    "stopping_metric": 'AUTO',
    "stopping_tolerance": 0.0001,
    'seed': 42
}

grid_search = H2OGridSearch(H2ORandomForestEstimator, hyper_parameters, search_criteria=search_criteria)
grid_search.train(x=events_names_x, 
                  y="total_rsvps", 
                  training_frame=train,
                  validation_frame=test)

一旦运行，我想打印模型并按AUC，

的顺序预测

grid_search.sort_by('auc', False)

我收到以下错误，

---------------------------------------------------------------------------
KeyError                                  Traceback (most recent call last)
<ipython-input-272-b250bf2b838e> in <module>()
----> 1 grid_search.sort_by('auc', False)

/Users/stereo/.pyenv/versions/3.5.2/lib/python3.5/site-packages/h2o/grid/grid_search.py in sort_by(self, metric, increasing)
    663 
    664         if metric[-1] != ')': metric += '()'
--> 665         c_values = [list(x) for x in zip(*sorted(eval('self.' + metric + '.items()'), key=lambda k_v: k_v[1]))]
    666         c_values.insert(1, [self.get_hyperparams(model_id, display=False) for model_id in c_values[0]])
    667         if not increasing:

/Users/stereo/.pyenv/versions/3.5.2/lib/python3.5/site-packages/h2o/grid/grid_search.py in <module>()

/Users/stereo/.pyenv/versions/3.5.2/lib/python3.5/site-packages/h2o/grid/grid_search.py in auc(self, train, valid, xval)
    606         :return: The AUC.
    607         """
--> 608         return {model.model_id: model.auc(train, valid, xval) for model in self.models}
    609 
    610     def aic(self, train=False, valid=False, xval=False):

/Users/stereo/.pyenv/versions/3.5.2/lib/python3.5/site-packages/h2o/grid/grid_search.py in <dictcomp>(.0)
    606         :return: The AUC.
    607         """
--> 608         return {model.model_id: model.auc(train, valid, xval) for model in self.models}
    609 
    610     def aic(self, train=False, valid=False, xval=False):

/Users/stereo/.pyenv/versions/3.5.2/lib/python3.5/site-packages/h2o/model/model_base.py in auc(self, train, valid, xval)
    669         tm = ModelBase._get_metrics(self, train, valid, xval)
    670         m = {}
--> 671         for k, v in viewitems(tm): m[k] = None if v is None else v.auc()
    672         return list(m.values())[0] if len(m) == 1 else m
    673 

/Users/stereo/.pyenv/versions/3.5.2/lib/python3.5/site-packages/h2o/model/metrics_base.py in auc(self)
    158         :return: Retrieve the AUC for this set of metrics.
    159         """
--> 160         return self._metric_json['AUC']
    161 
    162     def aic(self):

KeyError: 'AUC'

任何建议：

可以按性能顺序打印模型
使用最高AUC

Answer 1

你需要的是

require('@myorg/mypackage')

如果您愿意，可以将减少值更改为False

H2O Python API：从GridSearch中检索最佳模型

1 个答案: