Question

我正在尝试发布“fromdate”和“todate”来获取消息。当我运行下面的代码时，它会说“noHandlerFound”。所有的get方法都运行正常但不是Post方法。请帮帮我。

这是html代码。

QUERY = "insert into epic_foods.tellimuse_toidud (Toidukoht, Toit, Tyyp, 
Lisad, Ilma, Tellimuse_ID) values ('" & Toidud.cmbToidukoht.Text & "','" & 
Toidud.cmbToit.Text & "','" & Toidud.cmbTyyp.Text & "', '" & 
Toidud.lsbLisad.Text & "','" & Toidud.txtIlma.Text & "','" & 
Toidud.txtID.Text & "')"

Spring代码：

<form name="filtersForm" action="/SpringApp/getmessages" method="post">
    From Date: <input name="fromDate" type="date" value="01-01-2015" />
    To Date: <input name="toDate" type="date" value="01-03-2015" />
    <input name="submit" type="submit" value="submit" />
</form>

当我运行此代码时，我收到以下错误：

    @RequestMapping(value = "/getmessages", method = RequestMethod.POST)
public String getMessages(@RequestParam("fromDate") String start_dt, @RequestParam("toDate") String end_dt,
        ModelMap model) {

    SimpleDateFormat sdf = new SimpleDateFormat("dd-MM-yyyy hh:mm:ss");
    Date fromDate, toDate;
    try {
        fromDate = sdf.parse(start_dt);
        toDate = sdf.parse(end_dt);
        model.put("messagesList", appservice.getMessages(fromDate, toDate));
    } catch (ParseException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

    return "home";

}

这是WEB.XML文件。

org.springframework.web.servlet.PageNotFound noHandlerFound
WARNING: No mapping found for HTTP request with URI [/SpringApp/403] in DispatcherServlet with name 'mvc-dispatcher'

http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd” id =“WebApp_ID”version =“3.0”＆gt; MonitorApp

<?xml version="1.0" encoding="UTF-8"?>

Spring Security：

<context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>
        /WEB-INF/spring-security.xml,
        /WEB-INF/applicationContext.xml,
    </param-value>
</context-param>

<listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
    <servlet-name>mvc-dispatcher</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <load-on-startup>1</load-on-startup>
</servlet>

<servlet-mapping>
    <servlet-name>mvc-dispatcher</servlet-name>
    <url-pattern>/</url-pattern>
</servlet-mapping>

<!-- Spring Security -->
<filter>
    <filter-name>springSecurityFilterChain</filter-name>
    <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>

<filter-mapping>
    <filter-name>springSecurityFilterChain</filter-name>
    <url-pattern>/*</url-pattern>
</filter-mapping>

的ApplicationContext：

<beans:beans xmlns="http://www.springframework.org/schema/security"
xmlns:beans="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-4.3.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security-4.1.xsd">

<http auto-config="true" use-expressions="true">
    <intercept-url pattern="/**" requires-channel="http" />
    <intercept-url pattern="/"
        access="hasAnyRole('ROLE_ADMIN','ROLE_USER')" />
    <intercept-url pattern='/login' access='isAnonymous()' />
    <!-- access denied page -->
    <access-denied-handler error-page="/403" />

    <form-login login-page="/login" default-target-url="/home"
        authentication-failure-url="/login?error" login-processing-url="/j_spring_security_check"
        username-parameter="username" password-parameter="password" />

    <logout logout-success-url="/login?logout" logout-url="/j_spring_security_logout" />
    <!-- enable csrf protection -->
    <csrf />
</http>


<authentication-manager>
    <authentication-provider>
        <user-service>
            <user name="admin" password="admin" authorities="ROLE_ADMIN" />
            <user name="user" password="user" authorities="ROLE_USER" />
        </user-service>
    </authentication-provider>
</authentication-manager>

<?xml version="1.0" encoding="UTF-8"?>

Answer 1

尝试使用此解决方案here。

@Configuration
public class CreateYourSecurityConfig extends WebSecurityConfigurerAdapter {
  @Override
  protected void configure(HttpSecurity http) throws Exception {
    http.csrf().disable();
  }
}

Answer 2

我的问题通过更改getmessages的上下文路径得到解决？_csrf = a0008ebb-bed2-4245-89da-b012db364e99可能是因为安全性。

我们如何在Spring MVC中调用requestmethod = POST方法？

2 个答案: