Question

我的查询是

SELECT 
    CustBillPayment.CustomerId, CustBillPayment.Customer_Name, 
    CustBillPayment.CustBill_Total, CustBillPayment.CustBill_Paid,
    CustBillPayment.CustBill_ReamingAmt, CustBillPayment.Created_Date, 
    CustBillPayment.Delivery_Date, CustBillPayment.Updated_Date, 
    Shirt_Mes.Shirt_Type, Shirt_Mes.Shirt_Qty, Shirt_Mes.Shirt_Price, 
    Shirt_Mes.Shirt_Total, 
    Pant_Mes.Pant_Type, Pant_Mes.Pant_QTY, Pant_Mes.Pant_Total, 
    Pant_Mes.Pant_Price
FROM 
    ((CustBillPayment 
INNER JOIN
    Shirt_Mes ON CustBillPayment.CustomerId = Shirt_Mes.CustomerId) 
INNER JOIN
    Pant_Mes ON CustBillPayment.CustomerId = Pant_Mes.CustomerId) 
WHERE 
    CustBillPayment.CustomerId = 17

输出是这样的，显示了dublicate行：

CustomerId CustNm  SType   SQty SPrice  STotal PType    PQTY    PTotal  PPrice
-------------------------------------------------------------------------------
17         lakhan  sType1   2    200     400   PType3   3         900     300
17         lakhan  sType1   2    200     400   PType4   1         400     400
17         lakhan  sType2   1    250     250   PType3   3         900     300
17         lakhan  sType2   1    250     250   PType4   1         400     400

但我想要

CustomerId CustNm  SType   SQty SPrice  STotal PType    PQTY    PTotal  PPrice
-------------------------------------------------------------------------------
17         lakhan  sType1   2    200     400   PType3   3         900     300
17         lakhan  sType2   1    250     250   PType4   1         400     400

Answer 1

您不能SELECT DISTINCT，但其他人可能会觉得有帮助。您可以在编辑下找到答案。

关键字DISTINCT列出了唯一的行。要了解有关它的更多信息，请阅读：http://www.w3schools.com/sql/sql_distinct.asp。

修改

现在我看到了问题，我没有注意到数字不适合早些时候。在这种情况下，关键字DISTINCT无济于事。 JOIN首先加入Shirt_Mes表，但有两条记录，这意味着它将生成两行。下一个JOIN加入表Pant_Mes，条件也从该表中选择两个记录。前面的每一行都扩展了这两个记录。在这种情况下，它产生2 x 2行。

我猜，这是糟糕的表架构。您可以执行两个查询并将结果合并到应用程序逻辑中：

SELECT CustBillPayment.CustomerId, CustBillPayment.Customer_Name, CustBillPayment.CustBill_Total, CustBillPayment.CustBill_Paid, CustBillPayment.CustBill_ReamingAmt, CustBillPayment.Created_Date, CustBillPayment.Delivery_Date, CustBillPayment.Updated_Date, Shirt_Mes.Shirt_Type, Shirt_Mes.Shirt_Qty, Shirt_Mes.Shirt_Price, Shirt_Mes.Shirt_Total FROM CustBillPayment JOIN Shirt_Mes ON CustBillPayment.CustomerId = Shirt_Mes.CustomerId WHERE CustBillPayment.CustomerId=17

和

SELECT CustBillPayment.CustomerId, CustBillPayment.Customer_Name, CustBillPayment.CustBill_Total, CustBillPayment.CustBill_Paid, CustBillPayment.CustBill_ReamingAmt, CustBillPayment.Created_Date, CustBillPayment.Delivery_Date, CustBillPayment.Updated_Date, Pant_Mes.Pant_Type, Pant_Mes.Pant_QTY, Pant_Mes.Pant_Total, Pant_Mes.Pant_Price FROM CustBillPayment JOIN Pant_Mes ON CustBillPayment.CustomerId = Pant_Mes.CustomerId WHERE CustBillPayment.CustomerId=17

或者您可以将所有商品放在一张桌子上（我猜这是用于电子商店或类似的东西）。更好的是更改表模式，但如果您有充分的理由将货物存储在单独的表中（并且货物类型不是很好的理由），您可以执行以下查询：

SELECT CustBillPayment.CustomerId, CustBillPayment.Customer_Name, CustBillPayment.CustBill_Total, CustBillPayment.CustBill_Paid, CustBillPayment.CustBill_ReamingAmt, CustBillPayment.Created_Date, CustBillPayment.Delivery_Date, CustBillPayment.Updated_Date, Goods_Mes.Type, Goods_Mes.Qty, Goods_Mes.Price, Goods_Mes.Total FROM CustBillPayment JOIN (SELECT Shirt_Mes.Shirt_Type AS Type, Shirt_Mes.Shirt_Qty AS Qty, Shirt_Mes.Shirt_Price AS Price, Shirt_Mes.Shirt_Total AS Total, Shirt_Mes.CustomerId FROM Shirt_Mes UNION SELECT Pant_Mes.Pant_Type AS Type, Pant_Mes.Pant_Qty AS Qty, Pant_Mes.Pant_Price AS Price, Pant_Mes.Pant_Total AS Total, Pant_Mes.CustomerId FROM Pant_Mes ) Goods_Mes ON CustBillPayment.CustomerId = Goods_Mes.CustomerId WHERE CustBillPayment.CustomerId=17

为了更好地进行查询，您可以删除Shirt_Total和Pant_Total，并将Goods_Mes.Total替换为Goods_Mes.Qty * Goods_Mes.Price。

Answer 2

这应该有效：

SELECT DISTINCT CustBillPayment.CustomerId,
            CustBillPayment.Customer_Name,
            CustBillPayment.CustBill_Total,
            CustBillPayment.CustBill_Paid,
            CustBillPayment.CustBill_ReamingAmt,
            CustBillPayment.Created_Date,
            CustBillPayment.Delivery_Date,
            CustBillPayment.Updated_Date,
            Shirt_Mes.Shirt_Type,
            Shirt_Mes.Shirt_Qty,
            Shirt_Mes.Shirt_Price,
            Shirt_Mes.Shirt_Total,
            Pant_Mes.Pant_Type,
            Pant_Mes.Pant_QTY,
            Pant_Mes.Pant_Total,
            Pant_Mes.Pant_Price
  FROM ((CustBillPayment INNER JOIN Shirt_Mes ON CustBillPayment.CustomerId = Shirt_Mes.CustomerId) INNER JOIN
        Pant_Mes ON CustBillPayment.CustomerId = Pant_Mes.CustomerId)
 WHERE CustBillPayment.CustomerId = 17
 GROUP BY Shirt_Mes.Shirt_Type

Answer 3

尝试此查询

SELECT CBP.CustomerId, CBP.Customer_Name, 
       CBP.CustBill_Total, CBP.CustBill_Paid, 
       CBP.CustBill_ReamingAmt, CBP.Created_Date, 
       CBP.Delivery_Date, CBP.Updated_Date, 
       SMES.Shirt_Type, SMES.Shirt_Qty, SMES.Shirt_Price, 
       SMES.Shirt_Total, PMES.Pant_Type, PMES.Pant_QTY,    
       PMES.Pant_Total, PMES.Pant_Price 
FROM   CustBillPayment AS CBP 
LEFT JOIN Shirt_Mes AS SMES ON CBP.CustomerId = SMES.CustomerId 
LEFT JOIN Pant_Mes AS PMES ON CBP.CustomerId = PMES.CustomerId 
WHERE CBP.CustomerId = 17

Answer 4

区别和分组仅在记录唯一时才有效。

由于pant_type在每一行中不同，因此仍然会带回所有4行。对于小组来说也是如此。

您期望的最终输出是什么，因为top_type上的所需输出对于pant_type没有意义？

如何显示此输出？

4 个答案: