我有一个数据框,我希望在Rmarkdown中将其转换为具有正确对齐的表格
---
title: "Test"
output:
pdf_document
---
```{r testing, results='asis'}
library(xtable)
df <- structure(list(ID = c(101L, 102L, 103L, 104L, 105L, 106L),
Gr1 = c(10.76,983.4, 34.000, 20, 23.8457, 13.32),
Gr2 = c(NA,NA, NA, 20L, NA, NA)
),
.Names = c("ID", "Grade1", "Grade2"),
class = c("tbl_df", "data.frame"),
row.names = c(NA, -6L))
xtable(df,
align = c('l', 'p{1.5in}', rep('r{0.5in}',2)),
digits=c(0,0,1,0))
```
这给了我rep('r{0.5in}',2)
! LaTeX Error: Illegal character in array arg.
我也尝试过:align = c('l|', 'p{1.5in}|', rep('R{0.5in}|',2))
以下工作正常:align = c('l', 'p{1.5in}', rep('p{0.5in}',2))
但数据是左对齐的
答案 0 :(得分:1)
这是你桌子的近似值。我不知道我的宽度是完全正确的。显然pixiedust
发生了一些可疑的事情,因为当我将width_units
从"cm"
更改为"in"
时,我会得到一张太宽的表格。
---
title: "Test"
output:
pdf_document
header-includes:
- \usepackage{amssymb}
- \usepackage{arydshln}
- \usepackage{caption}
- \usepackage{graphicx}
- \usepackage{hhline}
- \usepackage{longtable}
- \usepackage{multirow}
- \usepackage[dvipsnames,table]{xcolor}
---
```{r testing, results='asis'}
library(pixiedust)
df <- structure(list(ID = c(101L, 102L, 103L, 104L, 105L, 106L),
Gr1 = c(10.76,983.4, 34.000, 20, 23.8457, 13.32),
Gr2 = c(NA,NA, NA, 20L, NA, NA)
),
.Names = c("ID", "Grade1", "Grade2"),
class = c("tbl_df", "data.frame"),
row.names = c(NA, -6L))
dust(df, keep_rownames = TRUE,
float = FALSE) %>%
sprinkle_colnames(.rownames = "") %>%
medley_bw() %>%
sprinkle_table(cols = ".rownames",
border = "right") %>%
sprinkle_table(cols = c("Grade1", "Grade2"),
halign = "right") %>%
sprinkle(cols = c("ID", "Grade1", "Grade2"),
width = c(1.5, 0.05, 0.05),
width_units = "cm",
na_string = "",
recycle = "cols") %>%
sprinkle(cols = "Grade1",
fn = quote(sprintf("%.1f", value)))
```
答案 1 :(得分:1)
解决了,我必须创建两个包含文件来注入必要的乳胶。首先在markdown文件上更新YAML:
---
title: "Test something"
output:
pdf_document:
includes:
in_header: preamble-latex.tex
before_body: prebody-latex.tex
---
<SNIP, SEE ABOVE>
然后创建preamble-latex.tex
以加载数组包
\usepackage{array}
创建prebody-latex.tex
以存储新列命令
\newcolumntype{R}[1]{>{\raggedleft\let\newline\\\arraybackslash\hspace{0pt}}p{#1}}