Question

我试图从用户那里收集一些数据并用用户输入显示。我给出的例子是：

Filename: output.txt
number of lines: 4
Line Length: 8
Character Set: ABC123

2CB3A32C
BB13CAA3
C3A21CB2
CC2B13A3

我目前已经获得了用户输入，但我不知道如何根据输入显示随机字母和数字。这是我的代码。任何帮助都会很大。必须使用循环显示数据。

public static void main(String[] args) throws IOException
{
    int lineNum = 0;
    int numChars = 0;
    String charSet = "";
    String userInput = "";
    String filename;

    //Creates a Scanner Object for keyboard input.
    Scanner keyboard = new Scanner(System.in);

    //Get the filename.
    System.out.print("Enter a filename: ");
    filename = keyboard.nextLine();

    System.out.print("Enter number of lines: ");
    lineNum = keyboard.nextInt();

    if( lineNum < 1 || lineNum > 20){
        lineNum = 20;
        System.out.println("Defaulting to 20 lines");
    }

    System.out.print("Enter number of characters in each line: ");
    numChars = keyboard.nextInt();
    keyboard.nextLine();

    if( numChars < 1 || numChars > 20){
        numChars = 20;
        System.out.println("Defaulting to 20 characters");
    }

    System.out.print("Enter character set: ");
    charSet = keyboard.nextLine();

    //Put all the input together to display the results 

    PrintWriter pw = new PrintWriter(filename);
    pw.println("\nFilename: " + filename);
    pw.println("Number of lines: " + lineNum );
    pw.println("Line Length: " + numChars );
    pw.println("Character set: " + charSet );
    pw.println("\n" + userInput );
    pw.close();

    // Read the file
    BufferedReader br = new BufferedReader(new FileReader(filename));
    for (String line; (line = br.readLine()) != null;) {
        System.out.println(line);
    }

}

Answer 1

试试这个。

Random random = new Random();
for (int i = 0; i < lineNum; ++i) {
    for (int j = 0; j < numChars; ++j)
        pw.print(charSet.charAt(random.nextInt(charSet.length())));
    pw.println();
}

Answer 2

看看：RandomStringUtils

这可能有助于您走上正确的轨道： import org.apache.commons.lang.RandomStringUtils; System.out.println(RandomStringUtils.random(8,new char[]{'a','b','c','1', '2', '3'}));

Answer 3

尝试：

str.charAt(ThreadLocalRandom.current().nextInt(0, str.length()));

Answer 4

在Java8中

final int length = 8;
final Random rand = new Random();
String random = IntStream.range(0, length).mapToObj(i -> str.charAt(rand.nextInt(100) % str.length()) + "").collect(Collectors.joining());
System.out.println(random);

为10次运行生成的随机字符串

A31CCCB3
1AC3A2CA
BAB11B2A
A33A1ACA
BCCCB2AC
331C12CA
3CC1AAB3
113BAABB
1BC22B1A
31BBCAC1

Answer 5

您可以使用以下的Utilty类

import java.util.Random;

public class RandomString {

  private char[] symbols;

  private final Random random = new Random();

  private final char[] buf;

  public RandomString(int length ,char[] symbols) {
    if (length < 1)
      throw new IllegalArgumentException("length < 1: " + length);
    buf = new char[length];
    this.symbols = symbols;
  }

  public String nextString() {
    for (int idx = 0; idx < buf.length; ++idx) 
      buf[idx] = symbols[random.nextInt(symbols.length)];
    return new String(buf);
  }
}

从您的主要使用

RandomString randString = new RandomString(numChars ,charSet.toCharArray());
        for (int i = 0; i < lineNum; i++) {
            System.out.println("" +randString.nextString());
        }

根据问题随机化用户输入

5 个答案: