Question

我有以下代码：

// company_ids is an array of mongo IDs
// company_id is an array (with only 1 element) of mongo ID
foreach($company_ids as $company_id){
    $results = Archive::where("billing.company._id", 'all', array($company_id))->get();
    ...

以下是Log::info(print_r($company_ids, true))

的输出

[2016-10-22 02:41:27] production.INFO: Array
(
    [0] => 57515764b91a8c4d008b45d1
    [1] => 57515764b91a8c4d008b45d6
    [2] => 57515764b91a8c4d008b45db
    [3] => 57515764b91a8c4d008b45e0
    ...
)

如何使用Archive直接查询company_ids集合并删除foreach循环的需要？

Answer 1

@Robbie 答案中的小更新。不需要使用MongoIds数组只需使用字符串数组就可以了。我只使用laravel-jenessengers

$company_ids = [
    '57515764b91a8c4d008b45d1',
    '57515764b91a8c4d008b45d6',
    '57515764b91a8c4d008b45db',
    '57515764b91a8c4d008b45e0'
]

$results = Archive::whereIn('billing.company._id', $company_ids)->get();

Answer 2

根据图书馆的readme：

$results = Archive::whereIn('billing.company._id', $company_ids)->get();

（我不清楚数组$ company_ids是什么，但我认为它需要和MongoID数组：但这也取决于您使用的基础库，Mongo或{{ 3}}，因为两者都得到了库的支持）

$company_ids = [
    new mongoID('57515764b91a8c4d008b45d1'),
    new mongoID('57515764b91a8c4d008b45d6'),
    new mongoID('57515764b91a8c4d008b45db'),
    new mongoID('57515764b91a8c4d008b45e0'),
]

使用mongoID数组查询集合

2 个答案: