Question

我试图将一些csv数据加载到一个spark群集中并在其上运行一些查询，但是我遇到了加载数据的问题。

请参阅下面的代码示例 - 我已经生成了一个标头并且正在尝试解析列，但是当针对（大的，富的列）数据集运行时，该过程失败，并显示模糊的错误消息：＆＃39; java.lang.String不是字符串＆＃39;

的模式的有效外部类型

这似乎无法在互联网上的其他地方解决 - 任何人都知道问题可能是什么？

（我原本以为这可能与正在加载的空字段或空字段有关，但是一段时间后进程失败，并且源数据非常稀疏）

var headers = StructType(header_clean.split(",").map(fieldName ⇒ StructField(fieldName, StringType, true)))
var contentRdd = contentNoHeader.map(k => k.split(",")).map(
    p => Row(p.map( x => x.replace("\"", "").trim)))

contentRdd.createOrReplaceTempView("someView")

val domains = spark.sql("SELECT DISTINCT domain FROM someView")

供参考，错误日志的底部（非常垃圾，很多列

if (assertnotnull(input[0, org.apache.spark.sql.Row, true], top level row object).isNullAt) null else staticinvoke(class org.apache.spark.unsafe.types.UTF8String, StringType, fromString, validateexternaltype(getexternalrowfield(assertnotnull(input[0, org.apache.spark.sql.Row, true], top level row object), 87, pageUrl), StringType), true) AS pageUrl#377
+- if (assertnotnull(input[0, org.apache.spark.sql.Row, true], top level row object).isNullAt) null else staticinvoke(class org.apache.spark.unsafe.types.UTF8String, StringType, fromString, validateexternaltype(getexternalrowfield(assertnotnull(input[0, org.apache.spark.sql.Row, true], top level row object), 87, pageUrl), StringType), true)    :- assertnotnull(input[0, org.apache.spark.sql.Row, true], top level row object).isNullAt    :  :- assertnotnull(input[0, org.apache.spark.sql.Row, true], top level row object)    :  :  +- input[0, org.apache.spark.sql.Row, true]    : 
+- 87    :- null    +- staticinvoke(class org.apache.spark.unsafe.types.UTF8String, StringType, fromString, validateexternaltype(getexternalrowfield(assertnotnull(input[0, org.apache.spark.sql.Row, true], top level row object), 87, pageUrl), StringType), true)
      +- validateexternaltype(getexternalrowfield(assertnotnull(input[0, org.apache.spark.sql.Row, true], top level row object), 87, pageUrl), StringType)
         +- getexternalrowfield(assertnotnull(input[0, org.apache.spark.sql.Row, true], top level row object), 87, pageUrl)
            +- assertnotnull(input[0, org.apache.spark.sql.Row, true], top level row object)
               +- input[0, org.apache.spark.sql.Row, true]   at org.apache.spark.sql.catalyst.encoders.ExpressionEncoder.toRow(ExpressionEncoder.scala:279) at org.apache.spark.sql.SparkSession$$anonfun$5.apply(SparkSession.scala:537) at org.apache.spark.sql.SparkSession$$anonfun$5.apply(SparkSession.scala:537) at scala.collection.Iterator$$anon$11.next(Iterator.scala:409)   at scala.collection.Iterator$$anon$11.next(Iterator.scala:409)   at org.apache.spark.sql.catalyst.expressions.GeneratedClass$GeneratedIterator.agg_doAggregateWithKeys$(Unknown Source)   at org.apache.spark.sql.catalyst.expressions.GeneratedClass$GeneratedIterator.processNext(Unknown Source)   at org.apache.spark.sql.execution.BufferedRowIterator.hasNext(BufferedRowIterator.java:43) at org.apache.spark.sql.execution.WholeStageCodegenExec$$anonfun$8$$anon$1.hasNext(WholeStageCodegenExec.scala:370) at scala.collection.Iterator$$anon$11.hasNext(Iterator.scala:408)   at org.apache.spark.shuffle.sort.BypassMergeSortShuffleWriter.write(BypassMergeSortShuffleWriter.java:125) at org.apache.spark.scheduler.ShuffleMapTask.runTask(ShuffleMapTask.scala:79) at org.apache.spark.scheduler.ShuffleMapTask.runTask(ShuffleMapTask.scala:47) at org.apache.spark.scheduler.Task.run(Task.scala:85)   at org.apache.spark.executor.Executor$TaskRunner.run(Executor.scala:274)  ... 3 more Caused by: java.lang.RuntimeException: [Ljava.lang.String; is not a valid external type for schema of string   at org.apache.spark.sql.catalyst.expressions.GeneratedClass$SpecificUnsafeProjection.apply_0$(Unknown Source)   at org.apache.spark.sql.catalyst.expressions.GeneratedClass$SpecificUnsafeProjection.apply(Unknown Source)   at org.apache.spark.sql.catalyst.encoders.ExpressionEncoder.toRow(ExpressionEncoder.scala:276) ... 17 more

Answer 1

我通过拆分Row的元素解决了这个问题。你可以这样做：

StructType(header_clean.split(",").map(fieldName ⇒StructField(fieldName, StringType, true)))
var contentRdd = contentNoHeader.map(k => k.split(",")).map(
p => {
  val ppp = p.map( x => x.replace("\"", "").trim)
  Row(ppp(0),ppp(1),ppp(2))
})

java.lang.String不是string的模式的有效外部类型

1 个答案: