从对象数组中获取对象属性值

Question

我有一个像这样的对象数组：

damages: [
        {
            name: "Roof",
            photos: [
                {image_url: "http://www.url1.com"},
                {image_url: "http://www.url2.com"},
                {image_url: "http://www.url3.com"},
           ]
        },
        {
            name: "Doors",
            photos: [
                {image_url: "http://www.url4.com"},
                {image_url: "http://www.url5.com"},
                {image_url: "http://www.url6.com"},
                {image_url: "http://www.url7.com"}
            ]
        }
    ]

如果我有image_url的值，我如何通过损坏来获取名称属性？

让我说我有这样的事情：

let image_url = "http://www.url6.com";
let name = damages.map(i => ....)    //"Doors"

Answer 1

你可以试试这样的东西吗？

var imgUrl = "http://www.url6.com";

for(var i = 0; i < damages.length; i++) {
    for(var j = 0; j < damages[i].photos.length; j++) {
        if(damages[i].photos[j].image_url === imgUrl) {
            console.log(damages[i].name);
        }
    }
}

Answer 2

X-Y

Answer 3

您可以使用Array#find和Array#some

function getName(url) {
    return damages.find(a => a.photos.some(b => b.image_url === url)).name;
}

var damages = [{ name: "Roof", photos: [{ image_url: "http://www.url1.com" }, { image_url: "http://www.url2.com" }, { image_url: "http://www.url3.com" }, ] }, { name: "Doors", photos: [{ image_url: "http://www.url4.com" }, { image_url: "http://www.url5.com" }, { image_url: "http://www.url6.com" }, { image_url: "http://www.url7.com" }] }];

console.log(getName('http://www.url6.com'));