First of all , the framework I'm using is Laravel 5.3
What I'm trying to accomplish is to find a way to minimize query in my application.I'm working on a restaurant web control panel , on the view wich I'm supposed to edit the list of dishes form respective categories assigned to a daily special menu.A preview of the view is shown below :
I have two queries that after some work done on their results, generate each a different array.
The first array named : $selectable_categories_and_dishes
returns an array of all the categories and dishes in the database(This includes the categories and respective dishes that are already selected).
Array's objects and structure :
{
"id_category":4,
"category_name":"Contorno ",
"dishes":[
{
"id":15,
"price":"10",
"name":"Patate al Forno"
},
{
"id":16,
"price":
"8","name":"Verdure alla Griglia"
},
{
"id":17,
"price":"8",
"name":"Insalata Mista"
}
],
}
The second array named : $selected_categories_and_dishes
returns an array of all the categories and dishes that were selected when the daily special menu was created in the first place .
Array's objects and structure :
{
"id_category":4,
"category_name":"Contorno ",
"dishes":[
{
"id":15,
"price":"10",
"name":"Patate al Forno",
"id_pcm":"4"
},
{
"id":16,
"price":"8",
"name":"Verdure alla Griglia",
"id_pcm":"4"
},
{
"id":17,
"price":"8",
"name":"Insalata Mista",
"id_pcm":"4"
}
],
}
What I can't figure out is a way to merge these arrays together in a way that when I loop the merged array , all the selected dishes are checked.
Does any one have any idea how to accomplish that.Any response is appreciated. Thanks in advance.
Edit:
The way I generate this arrays id as follows :
$menu_categories = DB::select('SELECT id , name FROM `packages_menu_categories` WHERE visible = "yes" AND `delete` = "no"');
$selectable_categories_and_dishes = array();
foreach ($menu_categories as $menu_category)
{
$dishes = DB::select('SELECT d.id , d.price , d.name FROM `package_menu_categories_dishes` p LEFT JOIN `dishes` d ON p.id_dish = d.id WHERE p.visible = "yes" AND p.delete = "no" AND p.id_package_menu_category ='.$menu_category->id);
$object=
[
'id_category' => $menu_category->id,
'category_name' =>$menu_category->name,
'dishes' => $dishes
];
array_push($selectable_categories_and_dishes,$object);
}
$selected_categories = DB::select('SELECT c.id as id_category , c.name as category_name FROM sub_packages_dishes s LEFT JOIN packages_menu_categories c ON s.id_package_menu_category = c.id WHERE s.id_sub_package = '.$id.' GROUP BY s.id_package_menu_category');
$dishes_and_categories = array();
foreach ($selected_categories as $selected_category)
{
$dishes = DB::select('SELECT s.id AS id_pmcd , d.id , d.name FROM `sub_packages_dishes` s LEFT JOIN `dishes` d ON s.id_dish = d.id WHERE s.id_sub_package ='.$id.' AND s.id_package_menu_category ='.$selected_category->id_category);
$object=
[
'id_category' => $selected_category->id_category,
'category_name' =>$selected_category->category_name,
'dishes' => $dishes
];
array_push($dishes_and_categories,$object);
}
答案 0 :(得分:1)
我的建议假设您可以控制数组的结构,将菜肴作为关联数组,将关键字作为菜单ID。然后循环检查您所在的那个是否存在于所选的
中基本上这将是一个结构:
{
"id_category":4,
"category_name":"Contorno ",
"dishes":{
15 => {
"price":"10",
"name":"Patate al Forno",
"id_pcm":"4"
},
16 => {
"price":"8",
"name":"Verdure alla Griglia",
"id_pcm":"4"
}
...
}
然后当你循环你的数组时,就像它一样简单。这可能不是百分之百,但可以解决问题。
foreach($selectable_categories_and_dishes as $key => $values){
if(isset($selected_categories['dishes'][$key])){
//This is selected so check the box.
}
}