Question

好的，我目前正在学习C ++课程并且在最近的任务中努力工作。但是，当我拿到我的成绩时，我得到67，因为该程序将无法编译。在我打开它之前，它在我的计算机上编译得很好。当我看到这条消息时，我进入我的程序，它没有被更改并运行它。该程序编译好！没有问题。在我写完前一句之后，我刚刚再次测试了它，并再次运行良好。

现在我在Mac上使用Xcode，而我的老师正在使用Windows Visual Studio。不确定版本或类似的东西。

她遇到问题的具体代码行如下：

int mineSpots[n][m];
for (int r = 0; r < n; r++){
    for (int c = 0; c < m; c++){
        mineSpots[r][c] = 0;
    }
}

该程序的整个代码如下:(如果您愿意，可以转到我的github页面并查看其中的代码。这是https://github.com/ravenusmc/minesweeper_helper）同样，有关为什么编译的任何帮助xcode而不是Visual Studio会很棒。

#include <iostream>
#include <string>
#include <fstream>

using namespace std;

//Global Constants
const int ROWS = 100;
const int COLS = 100;

//*******************************
//Prototype Functions
//*******************************

void buildArray(ifstream &, char [][COLS], int, int, int);
void showArray(ifstream &, ofstream &, char [][COLS], int, int, int);

//******************************
//Main Function

// ***************

int main(){

//Declaring all of the variables that I will be using in the program.
ifstream inputFile;
ofstream outputFile;

char mines[ROWS][COLS];
//Variables to keep track of the number of rows and columns.
int n, m;
//variable to keep track of the number of fields
int count = 1;

//Opening the file
inputFile.open("inputdata.txt");

//Opening/creating the file to which store the information in this program.
outputFile.open("outputdata.txt");

//Checking for errors in the file.
if (inputFile.fail())
{
    cout << "Error opening data file. Progam will now close. \n\n";
    //system("pause"); //This line is for Microsoft Visual studio users.
    exit(0);
}

//This loop will read the information from the file until it is empty.
while (!inputFile.eof()){

    //These two lines will read the numerical values in each file and then they will be used as a counter
    //for the loop.
    inputFile >> n;
    inputFile >> m;

    //If the both values are zero, the program knows to break the while loop. Also, if the values are out of range then
    //the loop will break as well.
    if (n == 0 && m == 0){
        break;
    }else if (n <= 0){
        outputFile << "Sorry, the number of rows you have is less than 0!" << endl;
        break;
    }else if (m > 100){
        outputFile << "Sorry, the number of columns you have is greater than 100!" << endl;
        break;
    }

    //Calling the function to build each of the 2D arrays
    buildArray(inputFile, mines, ROWS, n, m);

    //This line is simply to display the field for each array in the txt document.
    outputFile << "Field #" << count << endl;

    //This function will build the new arrays.
    showArray(inputFile, outputFile, mines, ROWS, n, m);

    //These lines ensure that there is a space between each array.
    cout << endl;
    outputFile << endl;

    //The count is incremented each pass to keep track of the field number.
    count++;
  }


//Closing the input file.
inputFile.close();
//Closing the output file.
outputFile.close();

system("pause"); //This line is for Microsoft Visual users.

return 0;

 }//End of main function

 //******************************
 //Functions
  //******************************

 //This function will build the array from the inputdata.txt file.
 void buildArray(ifstream &file, char values[][COLS], int rows, int n, int m){
    char row;

    //This for loop goes through the document to build the array.
    for (int r = 0; r < n; r++){
        for (int c = 0; c < m; c++){
            file >> row;
            values[r][c] = row;
        }
  }
 } // End of buildArray Function

 //This function will find all the mines and then output what it finds to      the outputdata.txt file.
   void showArray(ifstream &file, ofstream &outFile, char values[][COLS], int rows, int n, int m){

//Creating an array to hold the numbers for the mines. Each position
//Will be set to 0 at the start.
int mineSpots[n][m];
for (int r = 0; r < n; r++){
    for (int c = 0; c < m; c++){
        mineSpots[r][c] = 0;
    }
}

//This for loop is what will actually find the locations of the mines. It uses a counter to go through every position around
//a spot that has an '*' and counts to determine the correct number of mines   around that location.
for (int row = 0; row < n; row++) {
    for (int col = 0; col < m; col++) {
        if (values[row][col] == '*') {
            if ((row - 1 >= 0) && (col - 1 >= 0) ){
                mineSpots[row - 1][col - 1]++;
            }
            if (row - 1 >= 0){
                mineSpots[row - 1][col]++;
            }
            if ( (col < m - 1) && (row > 0)){
                mineSpots[row - 1][col + 1]++;
            }
            if (col - 1 >= 0){
                mineSpots[row][col - 1]++;
            }
            if (!(col >= m - 1)){
                mineSpots[row][col + 1]++;
            }

            if (col - 1 >= 0){
                mineSpots[row + 1][col - 1]++;
            }
            if ((row < n - 1) && (col < m - 1)){
                mineSpots[row + 1][col + 1]++;
            }
            mineSpots[row + 1][col]++;
        }
    }
}

//This for loop displays the array.
for (int r = 0; r < n; r++){
    for (int c = 0; c < m; c++){
        if (values[r][c] == '*'){
            outFile << '*';
        }else{
            outFile << mineSpots[r][c];
            }
        }
        cout << endl;
        outFile << endl;
}
}// End of showArray Function

C ++编译MAC OS X和Windows之间的问题

0 个答案: