Bluebird在源代码中抛出异常

Question

我正在将bluebirdjs用于nodejs应用程序。它从源代码中抛出异常。

行：try {throw new Error(); } catch (e) {ret.lastLineError = e;}

路径：bluebird / js / release / util.js

行：374

这个例外对我来说似乎没用。它只会抛出异常。删除这一行是否合理？

第3行的async.js中也存在相同的代码。

Answer 1

In IE an Error object will not have a .stack property unless it goes a through try catch. The .stack property is needed to see which line and file the code is in.

ret.lastLineError = new Error() would therefore only work in firefox and chrome