我有2个jsp页面。 我将数据从1个jsp发送到另一个作为GET请求。 现在我想在第二个jsp中显示输出数据,但我无法做到。
这是我的第一个jsp,即index.jsp
<%--
Document : Spago
Created on : 14 Oct, 2016, 2:06:12 PM
Author : ndoshi
--%>
<%@page import="java.io.InputStreamReader"%>
<%@page import="java.io.BufferedReader"%>
<%@page import="java.net.*"%>
<%@page contentType="text/html" pageEncoding="UTF-8"%>
<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>JSP Page</title>
<script>
setTimeout(function () {
document.location = "http://localhost:8080/demo/index.jsp";
}, 60000); // <-- this is the delay in milliseconds
</script>
</head>
<body>
<%
try {
String machine = InetAddress.getLocalHost().getCanonicalHostName();
String user="Niket";
URL url = new URL("http://localhost:8080/demo/db.jsp?machine=" + machine+"&user="+user);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setRequestMethod("GET");
conn.setRequestProperty("Accept", "application/json");
BufferedReader in = new BufferedReader(
new InputStreamReader(conn.getInputStream()));
String inputLine;
StringBuffer response1 = new StringBuffer();
while ((inputLine = in.readLine()) != null) {
response1.append(inputLine);
}
System.out.println(inputLine);
out.println("Index : "+inputLine);
in.close();
if (conn.getResponseCode() != 200) {
}
} catch (Exception e) {
}
%>
</body>
</html>
这是我的第二个jsp,即db.jsp
<%--
Document : db.jsp
Created on : 20 Oct, 2016, 1:29:47 PM
Author : ndoshi
--%>
<%@page contentType="text/html" pageEncoding="UTF-8"%>
<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>JSP Page</title>
</head>
<body>
<%
out.println("Response : "+request.getParameter("machine")+","+request.getParameter("user"));
%>
</body>
</html>
答案 0 :(得分:1)
您需要使用新代码修改以下代码。
旧代码:
String inputLine;
StringBuffer response1 = new StringBuffer();
while ((inputLine = in.readLine()) != null) {
response1.append(inputLine);
}
System.out.println(inputLine);
新代码
String inputLine;
String Line="";
while ((inputLine = in.readLine()) != null) {
Line+=inputLine;
}
out.println(Line);
StringBuffer在这种情况下不起作用。