表#Temp:
ID Name Hobbies
1 xxx Reading
1 xxx Sports
1 xxx Dance
2 xyz Dance
3 yyy Swimming
3 yyy Reading
现在,我希望结果集为:
ID Name Hobby1 Hobby2 Hobby3
1 xxx Reading Sports Dance
2 xyz Cooking
3 yyy Coloring Swimming
如何做到这一点?我已经使用了多个爱好值,所以我不能硬编码。
答案 0 :(得分:3)
由于您知道每个名称的最大爱好数量您可以为每个名称生成行号并将其用于旋转
;with data as
(
SELECT row_number()over(partition by [ID] order by [Hobbies])rn,*
FROM ( VALUES (1,'xxx','Reading'),
(1,'xxx','Sports'),
(1,'xxx','Dance'),
(2,'xyz','Dance'),
(3,'yyy','Swimming'),
(3,'yyy','Reading')) tc ([ID], [Name], [Hobbies])
)
SELECT [ID],
[Name],
[Hobby1] = Max(CASE WHEN rn = 1 THEN [Hobbies] END),
[Hobby2] = Max(CASE WHEN rn = 2 THEN [Hobbies] END),
[Hobby3] = Max(CASE WHEN rn = 3 THEN [Hobbies] END)
FROM data
GROUP BY [ID],
[Name]
结果:
╔════╦══════╦═════════╦══════════╦════════╗
║ ID ║ Name ║ Hobby1 ║ Hobby2 ║ Hobby3 ║
╠════╬══════╬═════════╬══════════╬════════╣
║ 1 ║ xxx ║ Dance ║ Reading ║ Sports ║
║ 2 ║ xyz ║ Dance ║ NULL ║ NULL ║
║ 3 ║ yyy ║ Reading ║ Swimming ║ NULL ║
╚════╩══════╩═════════╩══════════╩════════╝
答案 1 :(得分:1)
尝试这样
DECLARE @tbl TABLE(ID INT,Name VARCHAR(100),Hobbies VARCHAR(100));
INSERT INTO @tbl VALUES
(1,'xxx','Reading')
,(1,'xxx','Sports')
,(1,'xxx','Dance')
,(2,'xyz','Dance')
,(3,'yyy','Swimming')
,(3,'yyy','Reading');
SELECT p.*
FROM
(
SELECT tbl.*
,'Hobby' + CAST(ROW_NUMBER() OVER(PARTITION BY tbl.Name ORDER BY tbl.ID) AS VARCHAR(10)) AS ColumnName
FROM @tbl AS tbl
) AS t
PIVOT
(
MAX(Hobbies) FOR ColumnName IN(Hobby1,Hobby2,Hobby3,Hobby4 /*add more if needed*/)
) AS p
结果
ID Name Hobby1 Hobby2 Hobby3 Hobby4
1 xxx Reading Sports Dance NULL
2 xyz Dance NULL NULL NULL
3 yyy Swimming Reading NULL NULL
答案 2 :(得分:1)
试试这个......
<input type="text" id="43" name="textbox1">
<input type="text" id="85" name="textbox2">
<input type="text" id="10" name="textbox3">
<input type="text" id="25" name="textbox4">
<input type="text" id="99" name="textbox5">
<script>
document.getElementById("10")
.insertAdjacentHTML("afterend"
, "<input type=text id=123 name=textbox3-5 value=3.5>");
</script>