Question

我在php环境中使用以下代码：

<tr class="odd gradeX">
    <td><?php echo $blog_id; ?></td>
    <td><?php echo $blog_title; ?></td>
    <td><?php echo $cat_name; ?></td>
    <td class="center"><img width="50" src="<?php echo SITE_URL."assets/images/blog_images/$blog_image" ?>"/></td>
    <td class="center"><?php echo $uname; ?></td>
    <td class="center"><?php echo $added_date; ?></td>
    <td class="center"><?php echo $status; ?></td>
    <td class="center"><a data-toggle="modal" class="delete" data-id="<?php echo $blog_id; ?>" data-target="#myModal" href="<?php echo AD_SITE_URL."delete.php?name=blog&blog_id=$blog_id" ?>">Delete</td>
</tr>

当我点击delete链接时，它会显示一个带有以下代码的弹出框：

<form >
    <div class="modal-footer">
        <input type="submit" id="deletePost" class="btn btn-danger" name="submit" value="YES">
        <input type="submit" class="btn btn-success" name="submit" value="NO"  data-dismiss="modal">
    </div>
</form>

现在当我按下Yes按钮时，它应该显示data-id链接中的delete值，但每次它都显示我data-id delete 1}}价值。如何使用jQuery获取每个data-id链接<script> $(document).ready(function() { $("#deletePost").click(function() { var id = $(".delete").attr("data-id"); alert(id); }); }); </script>值？

我使用以下代码：

list_possible_states

Answer 1

您只需在模式中创建一个隐藏字段，并在每次用户点击删除链接时填充其值

这是工作演示

＆＃13;

$(function() {
  $(".delete").click(function() {
    id = $(this).data('id');
    $("#myModal #post-id").val(id);
  });
});

＆＃13;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://netdna.bootstrapcdn.com/bootstrap/3.1.1/js/bootstrap.min.js"></script>
<link href="https://netdna.bootstrapcdn.com/bootstrap/3.1.1/css/bootstrap.min.css" rel="stylesheet" />
<table class="table">
  <tr>
    <th>Id</th>
    <th>Title</th>
    <th>Category</th>
    <th>Desc</th>
    <th></th>
  </tr>
  <tr class="odd gradeX">
    <td>1</td>
    <td>title 1</td>
    <td>Category</td>
    <td class="center">data</td>
    <td class="center"><a data-toggle="modal" class="delete" data-id="1" data-target="#myModal" href="#">Delete</a>
    </td>
  </tr>
  <tr class="odd gradeX">
    <td>2</td>
    <td>title 2</td>
    <td>Category</td>
    <td class="center">data</td>
    <td class="center"><a data-toggle="modal" class="delete" data-id="2" data-target="#myModal" href="#">Delete</a>
    </td>
  </tr>
  <tr class="odd gradeX">
    <td>3</td>
    <td>title 3</td>
    <td>Category</td>
    <td class="center">data</td>
    <td class="center"><a data-toggle="modal" class="delete" data-id="3" data-target="#myModal" href="#">Delete</a>
    </td>
  </tr>
  <tr class="odd gradeX">
    <td>4</td>
    <td>title 4</td>
    <td>Category</td>
    <td class="center">data</td>
    <td class="center"><a data-toggle="modal" class="delete" data-id="4" data-target="#myModal" href="#">Delete</a>
    </td>
  </tr>
  <table>

    <div id="myModal" class="modal fade" tabindex="-1" role="dialog">
      <div class="modal-dialog" role="document">
        <div class="modal-content">
          <form>
            <div class="modal-header">
              <button type="button" class="close" data-dismiss="modal" aria-label="Close"><span aria-hidden="true">&times;</span>
              </button>
              <h4 class="modal-title">Modal title</h4>
            </div>
            <div class="modal-body">
              <p>Dou you want to delete</p>
              this is your hidden field for id
              <input type="text" name="id" id="post-id">
            </div>

            <div class="modal-footer">
              <input type="submit" id="deletePost" class="btn btn-danger" name="submit" value="YES">
              <input type="submit" class="btn btn-success" name="submit" value="NO" data-dismiss="modal">
            </div>
          </form>
        </div>
        <!-- /.modal-content -->
      </div>
      <!-- /.modal-dialog -->
    </div>
    <!-- /.modal -->

＆＃13;

我希望它会有所帮助

Answer 2

var id;
$("#tableid tbody").on('click','.delete', function(e){
    // show your modal
    id = $(this).attr("data-id");
});

Answer 3

每次单击此行的删除按钮，然后设置其他data-id属性以提交按钮

$('.delete').on('click',function(){
    $('[name=submit]').attr('data-id',$(this).data('id'));
})

＆安培;关闭数据模型，你可以删除该属性，（你可以在ajax成功点击提交时重复删除属性功能）

$('.close').on('click', function(){
   $('[name=submit]').removeAttr('data-id'))
})

如何使用jquery获取当前数据属性值？

3 个答案: