Question

我已经在NODE JS中编写了一个机器人，它将持续监控抽搐用户，当一些用户上线时，它会发送消息给＆＃34; group me＆＃34;用户在线的应用程序。它工作正常。我的问题是，有时它会发送用户在线但实际上用户处于离线状态的消息。关于如何解决这个问题的任何想法？

See screenshot

＆＃13;

var users = ["Statelinejay", "Ad_914", "Houssam06" ];
var messages = ["notsent", "notsent", "notsent" ];
var Client = require('node-rest-client').Client;
var client = new Client();
var express = require('express');
var request = require('request');

var app = express();

app.set('port', (process.env.PORT || 5000));


function theCall(index) {
    console.log('Processing ' + users[index]);

    client.get('https://api.twitch.tv/kraken/streams/' + users[index] + '?client_id=xxxxxxxxxxxxxxxxxxxxxxx', function (data, response) {
        if (data["stream"] === null) {
            messages[index] = 'notsent';
            console.log(users[index] + 'is offline');
        } else 
            //// Start of sending message
            var myJSONObject = {
                "bot_id": "xxxxxxxxxxxxxxxxxxxxxxxxxxxx",
                "text": " https://www.twitch.tv/" + users[index]
            };
            if (messages[index] === 'notsent') {
                request.post({
                        url: " https://api.groupme.com/v3/bots/post",
                        method: "POST",
                        json: true, // <--Very important!!!
                        body: myJSONObject
                    },

                    function (error, response, body) {
                        console.log(error);
                    }
                );
                messages[index] = 'sent';
                console.log('message sent');
            }
            //// End of sending message
            console.log(users[index] + '  is online') ;
        }
        theCall((++index % users.length));
    });
	
	
	 
	
}

app.listen(app.get('port'), function() {
  console.log('Node app is running on port', app.get('port'));
  theCall(0);
});

＆＃13;

Answer 1

当流媒体离线时，您确定数据[＆＃34; stream＆＃34;]始终为空吗？可以不定义吗？你能试试吗

if (!data["stream"])

而不是

if (data["stream"] === null)

如果这不起作用，你可以使用console.log记录虚假在线流媒体的数据和响应变量，并更新问题吗？

Twitch stream状态显示在线。用户离线时

1 个答案: